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3 years ago

At what rate is thermal energy being generated in the 2R-resistor when  = 12 V and R = 3.0 ?

1 answer:

8 0

If there's nothing else connected to the battery except the 3-ohm resistor, then the question is defective and the correct answer is not on the list.

With 12v connected across the resistor, the current through the resistor is

I = (E/R) = (12/3) = 4 Amperes.

The power generated inside a resistor is

P = (E x I) = (12v) x (4 A) = 48 watts

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In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average

Nady [450]

Answer:

191433.4 hours

Explanation:

We are given that In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average lifeexpectancy of an American)?

1 year - 365 days

Given that the television is on 6.75 hours/day.

If 1 year = 365 days

Convert 77.7 years to days by multiplying it by 365

77.7 × 365 = 28360.5 days

So the number of hours will be:

28360.5 × 6.75 = 191433.375 hours

Therefore, 191433.4 hours will pass.

Non of the options is correct.

6 0

3 years ago

Jenny loves puffed rice cereal. As she is pouring the cereal, two little

Ede4ka [16]

Answer:

4.9 x 10-23 N

Explanation:

I took the test

7 0

3 years ago

Read 2 more answers

Diffraction patterns are due to: interference refraction dispersion scattering

uranmaximum [27]

Diffraction patterns are due to interference. Diffraction is a phenomena which occurs when a wave encounters an obstacle. It is the bending of light around the corners if the obstacle.

3 0

3 years ago

Read 2 more answers

Two taut strings of identical mass and length are stretched with their ends fixed, but the tension in one string is 1.10 times g

ollegr [7]

Answer:

The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

Explanation:

Given;

velocity of wave on the string with lower tension, v₁ = 35.2 m/s

the fundamental frequency of the string, F₁ = 258 Hz

velocity of wave on the string with greater tension;

$v_1 = \sqrt{\frac{T_1}{\mu }$

where;

v₁ is the velocity of wave on the string with lower tension

T₁ is tension on the string

μ is mass per unit length

$v_1 = \sqrt{\frac{T_1}{\mu} } \\\\v_1^2 = \frac{T_1}{\mu} \\\\\mu = \frac{T_1}{v_1^2} \\\\ \frac{T_1}{v_1^2} = \frac{T_2}{v_2^2}\\\\v_2^2 = \frac{T_2v_1^2}{T_1}$

Where;

T₁ lower tension

T₂ greater tension

v₁ velocity of wave in string with lower tension

v₂ velocity of wave in string with greater tension

From the given question;

T₂ = 1.1 T₁

$v_2^2 = \frac{T_2v_1^2}{T_1} \\\\v_2 = \sqrt{\frac{T_2v_1^2}{T_1}} \\\\v_2 = \sqrt{\frac{1.1T_1*(35.2)^2}{T_1}}\\\\v_2 = \sqrt{1.1(35.2)^2} = 36.92 \ m/s$

Fundamental frequency of wave on the string with greater tension;

$f = \frac{v}{2l} \\\\2l = \frac{v}{f} \\\\thus, \frac{v_1}{f_1} =\frac{v_2}{f_2} \\\\f_2 = \frac{f_1v_2}{v_1} \\\\f_2 =\frac{258*36.92}{35.2} \\\\f_2 = 270.6 \ Hz$

Beat frequency = F₂ - F₁

= 270.6 - 258

= 12.6 Hz

Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

6 0

3 years ago

Find the net force for 10 N 10 N 25degree 5N 5N

icang [17]

Answer:

30n

Explanation:

7 0

3 years ago