Ask question

Ask question

All categories

3 years ago

5

The two oxygen atoms forming molecules of oxygen gas that you breath are joined by a polar covalent bond. Explain why this state

ment is true or false ?

1 answer:

mylen [45]3 years ago

5 0

It’s false. Anything that is bonded to itself is instantly a non-polar molecule as they both share the same electronegativity.

You might be interested in

(1) The solubility of Salt AB2(S) IS 5mol/dm^3.

Svetlanka [38]

Answer:

a. Ksp = 4s³

b. 5.53 × 10⁴ mol³/dm⁹

Explanation:

a. Obtain an expression for the solubility product of AB2(S),in terms of s.

AB₂ dissociates to give

AB₂ ⇄ A²⁺ + 2B⁻

Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as

AB₂ ⇄ A²⁺ + 2B⁻

1 : 1 : 2

Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s

So, we have

AB₂ ⇄ A²⁺ + 2B⁻

[s] [s] [2s]

So, the solubility product Ksp = [A²⁺][B⁻]²

= (s)(2s)²

= s(4s²)

= 4s³

b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³

Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³

Substituting the value of s into the equation, we have

Ksp = 4s³

= 4(2.4 × 10³ mol/dm³)³

= 4(13.824 × 10³ mol³/dm⁹)

= 55.296 × 10³ mol³/dm⁹

= 5.5296 × 10⁴ mol³/dm⁹

≅ 5.53 × 10⁴ mol³/dm⁹

Ksp = 5.53 × 10⁴ mol³/dm⁹

6 0

2 years ago

A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?

Nastasia [14]

Answer:

At -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where $P_{1}$ and $P_{2}$ are initial and final pressure respectively.

$V_{1}$ and $V_{2}$ are initial and final volume respectively.

$T_{1}$ and $T_{2}$ are initial and final temperature in kelvin scale respectively.

Here $P_{1}=150.0kPa$ , $V_{1}=1.75L$ , $T_{1}=(273-23)K=250K$ , $P_{2}=210.0kPa$ and $V_{2}=1.30L$

Hence $T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}$

$\Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}$

$\Rightarrow T_{2}=260K$

$\Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}$

So at -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

5 0

3 years ago

In the reaction 2 c o2 → 2 co, how many moles of carbon are needed to produce 66.0 g of carbon monoxide

weeeeeb [17]

The solution would be like this for this specific problem:

<span>Given:

</span>66.0 g of carbon monoxide

reaction 2 C + O2 → 2 CO

<span>mol e= mass / molar mass <span>
<span>mole of 2CO = 66.0g / (12.011 15.999)g / mol </span>
mole of 2CO = 2.36 (CO and C has a 1:1 mole ratio)

mole of 2CO = 2.36 -> mole of 1 CO = 2.36 / 2 = 1.18

<span>We got 2 moles of C, thus 1.18 x 2 = 2.36

So, we 2.36 </span>moles of carbon are needed to produce 66.0 g of carbon monoxide in the </span>reaction 2 C + O2 → 2 CO.</span> <span>To add, Carbon nonmetallic and tetravalent, thus, making four electrons available to form covalent chemical bonds. </span>

6 0

2 years ago

Which is the best molecule to build collegen, muscle repair, and tendon repair?

Licemer1 [7]

Answer:

d

Explanation:

collagen is made of proteins

4 0

3 years ago

Sodium acetate<br><br> NaC2H3O2<br><br> SC2H3O2<br><br> Na2C2H3O2

uysha [10]

Answer:

Sodium acetate is NaC2H3O2

7 0

2 years ago