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3 years ago

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A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chlor

oform in this solution. Round your answer to 3 significant digits?

1 answer:

user100 [1]3 years ago

7 0

Answer: the mole fraction for chloroform = 0.496

Explanation:Please see attachment for explanation

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