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maxonik [38]
3 years ago
7

These are two metamorphic rocks.

Chemistry
1 answer:
natima [27]3 years ago
3 0
It is either the 3rd choice or the first
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Which of the following are acids or bases?
Liono4ka [1.6K]

Answer:

1. Sodium hydrogen  - Base

2. Barium hydroxide solution  - Acid

3. Carbonate solution - Base

Explanation:

Please mark brainliest and have a great day!

3 0
3 years ago
The nucleus of an atom holds 4 neutrons and 4 protons, how many electrons does it have
sweet-ann [11.9K]
It has 4 electrons, because the number of protons and the number of electrons must be equal.
6 0
3 years ago
A metal that lost 2 electrons
Ymorist [56]

Answer:

is a member of IIA group

Explanation:

it has capacity to lose to electrons so that the become stable

8 0
3 years ago
Which of the following substances (with specific heat capacity provided) would show the greatest temperature change upon absorbi
JulijaS [17]

Answer:

Pb is the substance that experiments the greatest temperature change.

Explanation:

The specific heat capacity refers to the amount of heat energy required to raise in 1 degree the temperature of 1 gram of substance. The highest the heat capacity, the more energy it would be required. These variables are related through the equation:

Q = c . m . ΔT

where,

Q is the amount of heat energy provided (J)

c is the specific heat capacity (J/g.°C)

m is the mass of the substance

ΔT is the change in temperature

Since the question is about the change in temperature, we can rearrange the equation like this:

\Delta T = \frac{Q}{c.m}

All the substances in the options have the same mass (m=10.0g) and absorb the same amount of heat (Q=100.0J), so the change in temperature depends only on the specific heat capacity. We can see in the last equation that they are inversely proportional; the lower c, the greater ΔT. Since we are looking for the greatest temperature change, It must be the one with the lowest c, namely, Pb with c = 0.128 J/g°C. This makes sense because Pb is a metal and therefore a good conductor of heat.

Its change in temperature is:

\Delta T = \frac{q}{c.m} = \frac{100.0 J}{0.128 J/g.C . 10.0g } = 78.1

5 0
3 years ago
Read 2 more answers
A 48 kg sample of water absorbs 366 kJ of heat. the water was initially at 20.3 ∘C, what is its final temperature?
belka [17]

Answer:

The final temperature of water = 22.1224 °C

Explanation:

<u>Step 1</u> : defien the formula for heat transfer

q = m*c*ΔT

with q = heat transfer

with m = mass of the substance

with c = specific heat ( of water in this case)

with ΔT = difference between final temperature and initial temperature

In this case :

q=366kJ = 366 *10^3 J

mass of water = 48kg = 48000g

c= specific heat of wwater = 4.184 J / g °C

initial temperature = 20.3 °C

final temperature =  TO BE DETERMINED

<u>Step 2</u>: Calculate temperature

366000 J = 48000g * 4.184J/g °C * (T2 - 20.3)

366000 / (480000 * 4.184) = 1.8224 = (T2 - 20.3)

T2 = 20.3 + 1.82 =22.1224 ° C

The final temperature of water = 22.1224 °C

8 0
3 years ago
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