If 200mL of 0.60 M MgCl2 (aq) is added to 400mL of distilled water, what is the concentration of Mg2+(aq) in the resulting solut
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Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.
<h3>Definition of percent composition </h3>The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.
To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.
<h3>Percentage Composition in this case</h3>In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.
Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:
<u><em>percentage composition of potassium iodide= 0.017%</em></u>
Finally, the percent composition of potassium iodide in this sample is 0.017%.
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Explanation:
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In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:
Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:
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