If 200mL of 0.60 M MgCl2 (aq) is added to 400mL of distilled water, what is the concentration of Mg2+(aq) in the resulting solut

Question

2 years ago

5

ion with the total volume of 600mL? A.0.20M. B.0.30M. C.0.60M D.1.2M

1 answer:

lara [203] · Answer 1 · 2022-12-03T10:03:02+03:00

lara [203]2 years ago

3 0

Answer:

A.0.20M

Explanation:

c 1 V 1 = c 2 V 2

Initial Volume, V1 = 200 mL

Final Volume, V2 = 200 + 400 = 600 mL

Initial Concentration, c1 = 0.60 M

Final Concentration, c2= ?

Solving for c2;

c2 = c1v1 / v2

c2 = 0.60 * 200 / 600

c2 = 0.20M