The balanced equation for the above reaction is as follows
CaCO₃ + 2HBr ---> CaBr₂ + CO₂ + H₂O
stoichiometry of CaCO₃ to HBr is 1:2
number of moles of CaCO₃ reacted - 5.64 g / 100 g/mol = 0.0564 mol
according to molar ratio
number of HBr moles - 0.0564 mol x 2 = 0.1128 mol
number of HBr moles in 250.0 mL - 0.1128 mol
therefore number of HBr moles in 1000 mL - 0.1128 mol / 250.0 mL x 1000 mL = 0.4512 mol
molarity of HBr - 0.4512 M
To double the amount of sodium, you need to add the coefficient of <em>2</em>
Answer:
29127.6
Explanation:
1.11 MOLE ARE EQUAL TO 929.07 SO I DID THE MATH
Answer:
likely ionic
Explanation:
The bond between , Sodium and Bromine , in sodium bromide salt , is ionic in nature .
Since ,
The difference in the electronegativity of the two atom is high .
According to Pauling scale ,
The Electronegativity of Bromine = 2.96
The Electronegativity of sodium = 0.93
Hence ,
The Difference in electronegativity = ( 2.96 - 0.93 ) = 2.03
Hence ,
The electronegativity difference value is more than 1.8 ,
Therefore,
The bond is ionic in nature .