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Kamila [148]
3 years ago
15

Railway tracks are laid on large sized wooden sleepers.give reason

Physics
2 answers:
vampirchik [111]3 years ago
6 0

Answer:

rgndorgnodgkdjgkj

Explanation:

vredina [299]3 years ago
5 0
Train tracks use electricity and wood is both safe and a perfect foundation to start the process of building tracks
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A sprinter must average 24.0 mi/h to win a 100-m dash in 9.30 s. What is his wavelength at this speed if his mass is 84.5 kg?
crimeas [40]

Answer:

Wavelength λ = 7.31 × 10^-37 m

Explanation:

From De Broglie's equation;

λ = h/mv

Where;

λ = wavelength in meters

h = plank's constant = 6.626×10^-34 m^2 kg/s

m = mass in kg

v = velocity in m/s

Given;

v = 24 mi/h

Converting to m/s

v = 24mi/h × 0.447 m/s ×1/(mi/h)

v = 10.73m/s

m = 84.5kg

Substituting the values into the equation;

λ = (6.626×10^-34 m^2 kg/s)/(84.5kg × 10.73m/s)

λ = 7.31 × 10^-37 m

7 0
3 years ago
Read 2 more answers
Which of the following statements best describes the relationship between force and work?
viktelen [127]

a).,  b).,  and  c).  are completely false. 
There isn't a grain of truth among them.

In Physics, the technical definition of 'Work' is (force) times (distance).

7 0
3 years ago
What is the magnitude of the orbital velocity of the earth in m/s?
Lana71 [14]
Circumference C=2πr 
<span>C=2π(1.5x10^8)=9.42x10^8 </span>

<span>In 365 Days there are 8760hr </span>

<span>V=distance/time </span>

<span>V=(9.42x10^8)/8760=107534.2km/hr </span>
8 0
3 years ago
An object with a mass of 1500 g (grams) accelerates 10.0 m/s2 when an
masya89 [10]

Answer:

15N

Explanation:

F=ma

m=1500g = 1.5kg

a=10m/s2

1.5×10=15 N

8 0
3 years ago
Read 2 more answers
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
3 years ago
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