A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
1 answer:
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
= 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
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Answer:
temperature at 326.44 K system achieve equilibrium
Explanation:
given data
mass of block of ice = 4.6 kg
temperature = 263 K
thermal contact = 15.7-kg
specific heat of silver cAg = 233 J/kg-K
initially temperature = 1052 K
to find out
what temperature will the system achieve equilibrium
solution
first we consider final temperature of the system is T
we know that specific heat of water (C w) = 4186 J(kg K)
and
specific heat of ice ( C i ) = 2030 J/(kg K)
and
latent heat of fusion of ice ( Lf ) = 3.33 × J/kg
and we know that system is insulated
so heat lost by silver = heat generated by ice .................1
so we can say
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
put here value we get
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × + 4.6 × 4286 × ( T - 273 )
solve we get
T = 326.44 K
so temperature at 326.44 K system achieve equilibrium
Pluto would be placed 39.74 feet far from the Sun.
Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.
Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.
The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.
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Answer:
Frequency, f = 1 unit
Explanation:
It is given that,
Period of the wave, T = 1 unit
We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :
Or
f = 1 unit
So, the frequency of the wave is 1 unit. Hence, this is the required solution.