It is in its ground state when its orbital electron is at its lowest energy amount.
The andromeda galaxy is approaching our galaxy with a radial velocity of 120 km/s. given the galaxies present separation of 800 kpc, and neglecting both the transverse component of the velocity and the effect of gravity in accelerating the motion, estimate when the two galaxies will collide.
The Andromeda Galaxy, also known as Messier 31, M31, or NGC 224 and originally the Andromeda Nebula, is a barred spiral galaxy that is 2.5 million light-years away from Earth and the closest big galaxy to the Milky Way. It has a diameter of roughly 46.56 kiloparsecs.
The Milky Way, which houses the Solar System and Earth, and the Andromeda Galaxy are anticipated to collide in roughly 4.5 billion years. This galactic collision will take place between the two largest galaxies in the Local Group. The Andromeda galaxy is the brightest galaxy outside of our solar system. It is the furthest object that the majority of us humans can see with our unaided eyes at a distance of 2.5 million light-years.
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Answer:

Explanation:
Impulse on an object is given by
.
However, it's also given as change in momentum (impulse-momentum theorem).
Therefore, we can set the change in momentum equal to the former formula for impulse:
.
Momentum is given by
. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:
.
Now we plug in our values and solve:
(two significant figures).
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Answer:</h2>
Answers in the explanation
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Explanation:</h2>
The term speed is used to denote distance traveled divided by time. This can be expressed in a mathematical language as follows:

The cart with Low fan speed:

The cart with Medium fan speed:

The cart with High fan speed:

Answer:
298,220 N
Explanation:
Let the force on car three is T_23-T_34
Since net force= ma
from newton's second law we have
T_23-T_34 = ma
therefore,
T_23-T_34 = 37000×0.62
T_23= 22940+T_34
now, we need to calculate
T_34
Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2
F= ma
So, F= 12×37000×0.62= 22940×12= 275280 N
T_23 =22940+T_34= 22940+ 275280= 298,220 N
therefore, the tension in the coupling between the second and third cars
= 298,220 N