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Natali [406]
3 years ago
10

What is the magnitude of the orbital velocity of the earth in m/s?

Physics
1 answer:
Lana71 [14]3 years ago
8 0
Circumference C=2πr 
<span>C=2π(1.5x10^8)=9.42x10^8 </span>

<span>In 365 Days there are 8760hr </span>

<span>V=distance/time </span>

<span>V=(9.42x10^8)/8760=107534.2km/hr </span>
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Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How
zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

angle = \frac{1 Parsec}{distance}

so we have

distance = \frac{1 Parsec}{angle}

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

d_a = \frac{1 Parsec}{1} = 1 Parsec

distance of star B is given as

d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec

So star A is closer than star B

7 0
3 years ago
A ball rolls down a ramp. A small amount of friction heats up the ball. What energy transformations are taking place?
Natasha2012 [34]

Answer:kinetic energy converted to heat energy

Explanation:

As the ball rolls down kinetic energy is converted to heat energy

6 0
3 years ago
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How many basic states of matter exist?<br> three<br> two<br> five<br> four
djverab [1.8K]

Answer:

There are four basic states of matter

5 0
2 years ago
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Which of the following statements is true of a gas?
xenn [34]

Answer:

it takes the shape and size of the container that it is in

Explanation:

4 0
3 years ago
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You make a capacitor by cutting the 16.0-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.25 mm, and con
dalvyx [7]

Answer:

The capacitance of your capacitor is 5.476 x 10⁻⁵ μF

Explanation:

Given;

diameter of the aluminum pie plates = 16 cm = 0.16 m

separation distance, d = 3.25 mm = 0.00325 m

voltage across the parallel plates = 6 V

C = \frac{\epsilon A}{d}

where;

C is the capacitance of your capacitor

ε is the permittivity of free space = 8.85 x 10⁻¹²  (F/m)

d is separation distance

A is the area of the plate = ¹/₄ (πd²) = 0.25 (π x 0.16²) = 0.02011 m²

C = \frac{8.85*10^{-12} *0.02011}{0.00325} = 5.476 * 10^{-11} \ F = \ 5.476 * 10^{-5} \mu F

Therefore, the capacitance of your capacitor is 5.476 x 10⁻⁵ μF

3 0
3 years ago
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