3 years ago

What is the magnitude of the orbital velocity of the earth in m/s?

1 answer:

8 0

Circumference C=2πr
C=2π(1.5x10^8)=9.42x10^8 

In 365 Days there are 8760hr 

V=distance/time 

V=(9.42x10^8)/8760=107534.2km/hr

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