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ololo11 [35]
3 years ago
15

What is the equation of this line? y = 4x y=−14x y=14x y=−4x

Mathematics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

None of the given. It's

y = -1/4*x

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<img src="https://tex.z-dn.net/?f=789%20%5Ctimes%20%20%7B8%7D%5E%7B2%7D%20%20%3D%20" id="TexFormula1" title="789 \times {8}^{2}
Nikolay [14]

Answer:

50496

Explanation:

789 × 8 × 8 = 50496

------------------------------------------------------------------------------------

<em>Hope it helps, if you have any question, comment down below!</em>

5 0
3 years ago
Read 2 more answers
Your dad is putting a new circular swimming pool in the backyard that has the radius of 8 ft. If he wants to put bricks AROUND t
stira [4]

Answer:

2r*3.14= c

Step-by-step explanation:

2*8=16

16* 3.14=50.24

He will need 51 feet of brick

3 0
3 years ago
Read 2 more answers
what is the second term in a geometric sequence is 50. the forth term in the same sequence is 112.5 what is the common ratio in
Ulleksa [173]
The common ratio is 1.5 50 * 1.5 = 75, 75 * 1.5 = 112.5 etc.
7 0
3 years ago
An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden
Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

p_1=X_1/n_1=180/500=0.36

The sample 2, of size n2=600 has a proportion of p2=0.25.

p_1=X_1/n_1=150/600=0.25.

The difference between proportions is (p1-p2)=0.11.

p_d=p_1-p_2=0.36-0.25=0.11

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(t>3.964)=0.000078

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439

The  95% confidence interval for the population mean is (0.0556, 0.1644).

5 0
3 years ago
SIMPLIFY(5x3 - 12x + 4) + (6x2 - 4x + 3)
Iteru [2.4K]

Answer:

5x3-6x2-4x+7...(a)

Step-by-step explanation:

(5x3-12x+4)+ (6x2-4x+3)

15-12x+4+12-4x+3

5x3-6x2-4x+7

5 0
3 years ago
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