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SVEN [57.7K]
3 years ago
8

Compound a is an alkene that was treated with ozone (followed by dms) to yield only 4-heptanone. Draw the major product that is

expected when compound a is treated with mcpba followed by aqueous acid (h3o+).

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
5 0

Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive  cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.

Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.

The reaction is as shown in the image.

The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid H_3O^{+} is shown in the image.

m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.

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194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

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In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

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Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

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As the molecular mass of BCl₃ will be

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