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3 years ago

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Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ

g/ml. What is the protein concentration of the cod fish homogenate?

1 answer:

11111nata11111 [884]3 years ago

3 0

Answer:

Hallo

Explanation:

I took that question

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In every balanced chemical equation, each side of the equation has the same number of _____.

Ber [7]

The correct answer is option d, that is, atoms of the element.

As the atoms are neither destroyed nor created in a chemical reaction, the sum of the mass of the products in a reaction must be equivalent to the sum of the mass of the reactants.

The chemical reactions must be balanced, they must exhibit a similar number of atoms of each element on both the sides of the equation. As a consequence, the mass of the reactants must be equivalent to the mass of the products of the reaction.

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3 years ago

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Helium is listed as a noble gas true or false

Nonamiya [84]

True; Heilum is in Group 18 which are called “Noble Gases”

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4 years ago

You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

oksian1 [2.3K]

The empirical formula of this compound is equal to $Fe_{2}O_3$ .

<h3>Empirical formula</h3>

To calculate the empirical formula of a compound, it is necessary to know the number of moles present.

Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:

$MM_O = 16g/mol\\MM_Fe = 55.8g/mol$

$MM = \frac{m}{mol}$

Oxygen

$16 = \frac{4.8}{mol}$

$mol = 0.3$

Iron

$55.8 = \frac{11.2}{mol}$

$mol = 0.2$

Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:

O => $0.3 \times 10 = 3moles$

Fe => $0.2 \times 10 = 2moles$

So, the empirical formula of this compound is equal to $Fe_{2}O_3$

Learn more about empirical formula in: brainly.com/question/1363167

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3 years ago

Who turned the ragged Continental Army into a more efficient fighting force?

Goshia [24]

Von Steuben turned the ragged Continental Army into a more effective fighting force by drilling and teaching the army discipline

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3 years ago

What mass of Al would be obtained from the complete reduction of 10.2 tonnes of Al2O3?

Fynjy0 [20]

Answer:

5.4 tonnes.

Explanation:

The first step is to find the molar mass of Al2O3. Aluminum has a molar mass of about 27 and oxygen has a molar mass of about 16, so 2(27)+3(16)= 102g/mol=0.102kg/mol. 10200kg/0.102kg/mol=100,000 moles of Al2O3 in 10.2 tonnes. Multiplying this by the molar mass of the two aluminums, you get a total of 54*100,000=5400000g=5400kg=5.4 tonnes. Hope this helps!

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3 years ago