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galben [10]
3 years ago
15

Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ

g/ml. What is the protein concentration of the cod fish homogenate?
Chemistry
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

Hallo

Explanation:

I took that question

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What would you do to change a saturated solid/liquid solution to an unsaturated solution
Semenov [28]

Explanation:

Saturated solid/liquid solution is changed to an unsaturated solution by the dilution process.

When the saturated solution is diluted by addition large quantity of solvent it changed to an unsaturated solution.

Saturated solid/liquid solution can also be changed to an unsaturated solution by increasing the temperature or heating the solution.

A saturated solution is a solution where further solute will not dissolve in the solvent.

An unsaturated solution is a solution in which has the ability to dissolve more solute.

4 0
2 years ago
You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0
3 years ago
A ball is dropped from a height of 20 meters. At what height does the ball have a velocity of 10 meters/second?
musickatia [10]

Answer:

15m

Explanation:

vi = 0

vf = 10

a = -9.8

10^2 = 0 + 2(-9.8)(x2-x1) = -5.1

20-5.1 = 14.9m = 15m

3 0
2 years ago
What is the formula for sulfur hexa fluoride?
vlabodo [156]
S2F6, is the correct answer I believe!
6 0
2 years ago
Read 2 more answers
What is the weighted average of a nail in the sample data given?
Natalka [10]

The weighted average of the nail in accordance with the given data is 11.176g.

<h3>How to calculate weighted average?</h3>

Weighted average is an arithmetic mean of values biased according to agreed weightings.

The weighted average of the nail in the image above can be calculated by multiplying the decimal abundance with the mass of the nail, then summed up as follows;

Weighted average = (decimal abundance × mass 1) + (decimal abundance × mass 2)

Weighted average = (0.12 × 3.3) + (0.88 × 12.25)

Weighted average = 0.396 + 10.78

Weighted average = 11.176g

Therefore, 11.176g is the weighted average of the nail

Learn more about weighted average at: brainly.com/question/28042295

#SPJ1

5 0
1 year ago
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