Question

An object experiences an acceleration of 9.8 m/s over a distance of 210 m . After that acceleration it has a velocity of 380 m/s. What was it’s velocity before being accelerated

Answer 1

374.5m/s

Explanation:

acceleration, a = 9.8m/s²

distance, s = 210m

final velocity, v = 380m/s

unknown:

Initial velocity, u = ?

Solution:

We need to apply one of the equations of motion to solve this problem. The most fitting one is:

   V² = U² + 2as

   U is the unknown:

        U² = V² - 2as

        U² = 380² - 2x 9.8 x 210

        U² =  144,400‬ - 4,116‬ = 140284‬

        U = √140284‬ = 374.5m/s

Learn more:

Motion brainly.com/question/5248528

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