Question

An electron undergoes a transition from an initial (ni) to a final (nf ) energy state. The energies of the ni and nf energy states are −2.179×10−18J and −8.720×10−20 J, respectively.. . Calculate the wavelength (λ) of the light in nanometers (nm) corresponding to the energy change (ΔE) value of this transition. You can use the following values for your calculations:. . Planck′s constant (h) = 6.626×10−34 J⋅s. speed of light (c) = 2.998×108 m/s. 1 m = 109 nm

Answer 1

The equation for the energy (E) of the electron may be obtained by the equation,
                                             E = hc / λ
where h is Planck's constant, c and λ are speed of light and wavelength, respectively. Substituting the values,
              (-2.179x10^-18 - -8.720x10^-20) = (6.626x10^-34)(2.998x10^8)/ λ
From the equation, the value of λ is approximately equal to 9.496x10^-8 m.