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Sergio [31]
4 years ago
9

A gymnast's backflip is considered more difficult to do in the layout (straight body) position than in the tucked position. Why?

- The body's rotational inertia is greater in layout position than in tucked position. Because the body remains airborne for roughly the same time interval in either position, the gymnast must have much greater kinetic energy in tucked position to complete the backflip. - The body's rotational inertia is greater in tucked position than in layout position. Because the body remains airborne for roughly the same time interval in either position, the gymnast must have much greater kinetic energy in layout position to complete the backflip. - The body's rotational inertia is greater in layout position than in tucked position. Because the body remains airborne for roughly the same time interval in either position, the gymnast must have much greater kinetic energy in layout position to complete the backflip. - The body's rotational inertia is greater in tucked position than in layout position. Because the body remains airborne for roughly the same time interval in either position, the gymnast must have much greater kinetic energy in tucked position to complete the backflip.
Physics
1 answer:
spin [16.1K]4 years ago
6 0

Answer:

The body's rotational inertia is greater in layout position than in tucked position. Because the body remains airborne for roughly the same time interval in either position, the gymnast must have much greater kinetic energy in layout position to complete the backflip.

Explanation:

A gymnast's backflip is considered more difficult to do in the layout (straight body) position than in the tucked position.

When the body is straight , its moment of rotational inertia is more than the case when he folds his body round. Hence rotational inertia ( moment of inertia x angular velocity ) is also greater. To achieve that inertia , there is need of greater imput of energy in the form of kinetic energy  which requires greater effort.

So a gymnast's backflip is considered more difficult to do in the layout (straight body) position than in the tucked position.

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A 481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. What length does the observer measure for the spaces
galben [10]

Answer:

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

using the concept of length contraction, we have

L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}

where,

L' is the observed length

c is the speed of the light

Thus,

on substituting the respective values, we get

481=\frac{L'}{\sqrt{1-\frac{(2.70\times10^8)^2}{(3\times10^8)^2}}}

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3 0
4 years ago
A rock is dropped from a vertical cliff. The rock takes 3.00 s to reach the ground below the cliff. A second rock is thrown vert
Phantasy [73]

Answer:

Velocity v= 12.25 \frac{m}{s}

Explanation:

The first rock dropped give the distance Y in meters

Y_{f}=Y_{o}+v_{o}*t +\frac{1}{2}*a*t^{2}\\   Y_{f}=\frac{1}{2}* 9.8 \frac{m}{s^{2} }* 3^{2}   \\Y_{f}=44.1 m

Now the motion of the second rock the time change so to know the velocity

Y_{f}= Y_{o} +v_{o}*t +\frac{1}{2}*a *t^{2} \\v_{o}*t= -Y_{f} +\frac{1}{2} *a*t^{2} \\v_{o} =\frac{-44.1 +0.5 * 9.8* s^{2} }{2} \\v_{o}=  12.25 \frac{m}{s}

7 0
3 years ago
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
Marrrta [24]

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s

Hence, the time interval of the marble is 6.09 seconds.

6 0
4 years ago
Two children want to balance horizontally on a seesaw. The first child is sitting one meter to the left of the pivot point locat
Natali [406]

Answer:

d. 2m to the right of the pivot

Explanation:

m1 = m

m2 = 0.5m

d1 = 1m

d2 = ?

from principle of moment,

CWM = ACWM

m × 1 = 0.5m × d2

d2 = m/0.5m

= 1/0.5

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The 2nd child will have to sit 2m to the right

The turning effect of a force is known as the moment. It is the product of the force multiplied by the perpendicular distance from the line of action of the force to the pivot or point where the object will turn.

The principle of moments states that when in

equilibrium the total sum of the anti clockwise

moment is equal to the total sum of the

clockwise moment.

When a system is stable or balance it is said to be in equilibrium as all the forces acting on the system cancel each other out.

In equilibrium

Total Anticlockwise Moment = Total

Total Anticlockwise Moment = TotalClockwise Moment

4 0
3 years ago
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