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valentina_108 [34]
3 years ago
8

What is a prime factorization of 32

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

=2*2*2*2*2 = 2^5

Step-by-step explanation:

Prime factorization means getting to prime numbers

32 = 4*8

    = 2*2  * 4*2

    = 2*2 * 2*2*2

   = 2^5

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What are the values of h and x in the right triangle? Explain.
alexandr402 [8]

Answer:

h = 60 ; x = 25

Step-by-step explanation:

You are going to want to use Pythagorean Theorem to solve these.

Pythagorean Theorem: a² + b² = c²

h² + 144² = 156²

h² + 20736 = 24336

h² = 3600

h = 60

x² + 60² = 65²

x² + 3600 = 4225

x² = 625

x = 25

3 0
3 years ago
Find the volume of the pool shown. It consists of two prisms.
AfilCa [17]
The volume of the pool is 1,620 ft cubed
7 0
3 years ago
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Please help
user100 [1]

Answer:

Length of garden will be 30 metres.

Step-by-step explanation:

Let the Width of garden be x metres.

then,

Length of garden will be (x+6) metres.

Area = Length × Breadth

720 = x X (c+6)

720 = x²+6x

0 = x²+6x-720

As we can see above equation is a quadratic equation in the form of ax²+bx+C.

so,

=  \frac{ - b ±  \sqrt{{b}^{2} - 4ac}  }{2a}  \\ =   \frac{ - 6 ±   \sqrt{{6}^{2} - 4 \times 1 \times  - 720}  }{2}  \\ =    \frac{ - 6 ±  \sqrt{36 + 2880} }{2}  \\  =   \frac{ - 6 ±  \sqrt{2916} }{2}  \\  =   \frac{ - 6 ± 54}{2}\\= \frac{-6+54}{2} ... \frac{ - 6 - 54}{2}  \\  =  \frac{48}{2} ... \frac{ - 60}{2}  \\  = 24... - 30

One of the Roots of the Quadratic equation is 24 and other is -30.

And as we know width of any garden cannot be negative so the width of garden will be 24 metres.

As we got the width,

adding 6 to it will give us the Length,

So,

24 metres + 6 = 30 metres.

Length of the garden is 30 metres.

Hope It Helped You ;)

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@khuturr_

8 0
3 years ago
ASAP PLZ
Cloud [144]

Answer:

3/9 because theyre both equivalent to 1/3

8 0
3 years ago
Read 2 more answers
I need help with this, please. Any advice would be appreciated.
mote1985 [20]

Answer:

see explanation

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

where a₁ is the initial value and d the common difference

Given

S_{n} = \frac{n}{2} [ 10 + (n - 1)3 ]

Then by comparison

2a₁ = 10 ( divide both sides by 2 )

a₁ = 4 ← initial value

and d = 3 ← common difference

Thus

S_{8} = \frac{8}{2} [ 10 + (7 × 3) ]

   = 4(10 + 21)

   = 4 × 31

   = 124

8 0
3 years ago
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