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aalyn [17]
4 years ago
12

On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes.

Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?
Being willing to assume that the distribution of actual birthday lunch times for all employees at the company is approximately normal

Knowing that there are no outliers in the data as indicated by the normal probability plot and boxplot

Using a t-statistic to carry out the test

Using 9 for the number of degrees of freedom

Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.
Mathematics
1 answer:
yanalaym [24]4 years ago
6 0

Answer:

Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes

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When a number is decreased by 79% the result is 13 what is the original number to the nearest tenth
ASHA 777 [7]

Answer:

The number  is 61.9

Step-by-step explanation:

Let

x ----> the original number

Remember that

100\%-79\%=21\%=\frac{21}{100}

we know that

The original number multiplied by the fraction 21/100 must be equal to the number 13

so

The linear equation that model this situation is

\frac{21}{100}x=13

solve for x

Multiply by 100 both sides

21x=1,300

Divide by 21 both sides

x=\frac{1,300}{21}=61.9

8 0
4 years ago
Use a calculator to find the approximate angle measure of the following : cos^-1 (1/4)
Strike441 [17]

Answer:

75.52^o

Step-by-step explanation:

Let

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we have

cos(x)=\frac{1}{4}

using a calculator

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x=cos^{-1}(\frac{1}{4})

x=75.52^o

3 0
3 years ago
What simple interest rate is needed for $1000 to grow to $1071.25 in 9 months?
BlackZzzverrR [31]

Answer:

9.5%

Step-by-step explanation:

Use the formula I = Prt

I is the interest (unknown), P is the principal (1000), rate is the percent (unknown), and t is time in years (9/12).

9 months is a fraction of a year. There are 12 months in a year, so our fraction is 9/12. You can reduce this fraction by dividing by 3. The fraction reduced is 3/4. You can also use the decimal which is .75.

First we need to solve how much interest we earned. 1071.25 is the balance, so we need to subtract the principal from the balance.

1071.25 - 1000 = 71.25

Plug the numbers in to the formula. We are solving for r.

71.25 = 1000(.75)r

71.25 = 750r

71.25/750 = 750r/750

r = 0.095

Convert the decimal to a percent by moving the decimal two places right.

0.095 = 9.5%

3 0
2 years ago
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balandron [24]
4768 x 1551 is 7395168
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3 0
4 years ago
Read 2 more answers
Can u pls help me with this question
Anastasy [175]

Answer:

D

Step-by-step explanation:

$65-$39=$26 increase

$26/$39=.6667 or 66.67%

3 0
3 years ago
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