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3 years ago

What are the seven types of electromagnetic waves?

1 answer:

5 0

Radio waves. Giant satellite-dish antennas pick up long-wavelength, high-frequency radio waves. ...
Microwaves. Because cosmic microwaves can't get through the whole of Earth's atmosphere, we have to study them from space. ...
Infrared. ...
Visible light. ...
Ultraviolet light. ...
X rays. ...
Gamma rays.

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A 105 kg football player runs at 8.5 m/s and plows into the back of an 85 kg referee running at 3.5 m/s on the field causing the

Vedmedyk [2.9K]

Answer:

680 Kg.m/s

Explanation:

Mass of player; m_p = 105 kg.

Speed of player before Collision; v_pi = 8.5 m/s

Mass of referee; m_r = 85 kg

Speed of referee before collision; v_ri = 3.5 m/s

Speed of referee after collision; v_rf = 6 m/s

From conservation of momentum,

Initial momentum = final momentum

Thus;

(m_p × v_pi) + (m_r × v_ri) = (m_p × v_pf) + (m_r × v_rf)

Where (m_p × v_pf) is the momentum of the player after collision.

Thus, Plugging in the relevant values, we have;

(105 × 8.5) + (85 × 3.5) = (m_p × v_pf) + (85 × 6)

(m_p × v_pf) = (105 × 8.5) + (85 × 3.5) - (85 × 6)

(m_p × v_pf) = 680 Kg.m/s

3 0

3 years ago

What is the magnitude of a point charge that produces a potential of -200V at a distance of 1.00 mm?

schepotkina [342]

Answer:

$q=-2.22*10^{-11}C$

Explanation:

The potential produces by a point charge is given by:

$V=\frac{kq}{r}$

Here, k is the Coulomb constant, q is the signed magnitude of the point charge and r is the distance between the charge and the point at which the electric potential is measured. Solving for q:

$q=\frac{rV}{k}\\q=\frac{1*10^{-3}m(-200V)}{8.99*10^9\frac{V\cdot m}{C}}\\q=-2.22*10^{-11}C$

5 0

3 years ago

8. Before leaving the ground an airplane traveling with constant acceleration makes a run on the

Effectus [21]

Answer:

$\color{Blue}\huge\boxed{Answer}$

<h3>B. Speed at which it leaves the ground</h3>

8 0

3 years ago

Read 2 more answers

Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo

Tresset [83]

Answer:

The velocity with which the mass will hit the floor is $v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}$

Explanation:

If the tension in the string is $T$ , for $m_1$ we have

$T- m_1g =m_1a$ ,

and for the mass $m_2$

$T -m_2g = -m_2a$

From these equations we solve for $a$ and get:

$a =(\dfrac{m_2-m_1}{m_2+m_1}) g.$

The kinematic equation

$v_f^2 = v_0^2+2ax$

gives the final velocity $v_f$ of a particle, when its initial velocity was $v_0$ , and has traveled a distance $x$ while undergoing acceleration $a$ .