The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

Then, the final velocity will be

Thus, the final velocity of the truck is found as 146.969 m/s.
Answer:
When we double the angular velocity the maximum acceleration
will changes by a factor of 4.
Explanation:
Given the angular frequency
of the simple harmonic oscillator is doubled.
We need to find the change in the maximum acceleration of the oscillator.

Now, according to the problem, the angular frequency
got doubled.
Let us plug
. Then the maximum acceleration will be 



We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.
The best choice would be letter C hope this helps
The distance covered is 115 m
Explanation:
The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

where
s is the distance covered
u is the initiaal velocity
v is the final velocity
t is the time elapsed
In this problem, we have:
u = 4.20 m/s
v = 5.00 m/s
t = 25.0 s
Therefore, we can re-arrange the equation to find the distance covered:

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