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horsena [70]
3 years ago
14

A LOT OF POINTS! In your own words, compare and contrast transverse and longitudinal waves. Be sure to include at least one simi

larity and one difference
Physics
1 answer:
tatiyna3 years ago
5 0
Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.

To understand this it is good to think of a rope being held still by person B and being moved up and down by person A. The direction of propagation is from person A to B, so you will see the waves move along this way. But the displacement will be up and down.

Can travel in solids, but not in liquids and gas.

eg. Electromagnetic radiation

Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

A good example for this is a slinky being pushed along the table, the propagation will be along the table and so will the displacement of all the 'rings'.

Can travel through all states of matter.

eg. Sound waves
You might be interested in
Exoplanets (planets outside our solar system) are an active area of modern research. Suppose astronomers find such a planet that
Leno4ka [110]

Answer:

8.829 m/s²

Explanation:

M = Mass of Earth

m = Mass of Exoplanet

g_e = Acceleration due to gravity on Earth = 9.81 m/s²

g = Acceleration due to gravity on Exoplanet

m=M-0.1M\\\Rightarrow m=0.9M

g_e=G\frac{M}{r^2}

g=G\frac{0.9M}{r^2}

Dividing the equations we get

\frac{g}{g_e}=\frac{G\frac{0.9M}{r^2}}{G\frac{M}{r^2}}\\\Rightarrow \frac{g}{g_e}=0.9\\\Rightarrow g=0.9g_e\\\Rightarrow g=0.9\times 9.81\\\Rightarrow g=8.829\ m/s^2

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²

3 0
3 years ago
For a top player, a tennis ball may leave the racket on the serve with a speed of 55 m/s (about 120 mi/h). If the ball has a mas
inn [45]

Answer:

Yes is large enough

Explanation:

We need to apply the second Newton's Law to find the solution.

We know that,

F= ma

And we know as well that

a= \frac{v}{t}

Replacing the aceleration value in the equation force we have,

F= \frac{mv}{t}

Substituting our values we have,

F= \frac{(0.060)(55)}{4*10^{-3}}

F=825N

The weight of the person is then,

W = mg

W = (60)(9.8) = 558N

<em>We can conclude that force on the ball is large to lift the ball</em>

6 0
3 years ago
This is a machine consisting of two wheels of different sizes that rotate together. It is a modified lever.
tiny-mole [99]
Your answer is a Wheel and Axel.
3 0
3 years ago
A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragste
dezoksy [38]
You start by writing down your parameters;
u=60m/s
v=0
t=8s
So acceleration(a)=v-u/t
=0-60/8
=-60/8
=-7.5m/s
To the nearest hundredth will be
-7.5*100
=-750m/s
8 0
3 years ago
What is the net force on these free body diagrams?
pentagon [3]

A

The horizontal force cancels out. The two 4Ns go in opposite directions. So they don't affect the outcome.

The Vertical force is 6N up - 2 N down = 4 N Up

Answer 4 N up

B

The horizontal and vertical forces cancel out. Each gives 3N - 3N =0

The net force is 0

C

You only have horizontal forces on this one

5N - 3N = 2N  

The answer is 2N to the right.

7 0
3 years ago
Read 2 more answers
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