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horsena [70]
3 years ago
14

A LOT OF POINTS! In your own words, compare and contrast transverse and longitudinal waves. Be sure to include at least one simi

larity and one difference
Physics
1 answer:
tatiyna3 years ago
5 0
Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.

To understand this it is good to think of a rope being held still by person B and being moved up and down by person A. The direction of propagation is from person A to B, so you will see the waves move along this way. But the displacement will be up and down.

Can travel in solids, but not in liquids and gas.

eg. Electromagnetic radiation

Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

A good example for this is a slinky being pushed along the table, the propagation will be along the table and so will the displacement of all the 'rings'.

Can travel through all states of matter.

eg. Sound waves
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A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volu
WINSTONCH [101]

Answer:

6g/cm³

Explanation:

Density is the mass per unit volume of any substance. To solve this problem:

   

   Density  = \frac{mass}{volume}  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = \frac{600}{100}    = 6g/cm³

4 0
3 years ago
A wave oscillates 5.0 times a second and has a speed of 4.0m/s what is the frequency of this wave
Viefleur [7K]

Answer:

The frequency of the wave is 5.0Hz

Explanation:

The frequency of a wave is the number of oscillations or revolutions made in a second.

7 0
3 years ago
A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el
GuDViN [60]

Answer:

7.2\cdot 10^{-19} J

Explanation:

The change in electrical potential energy of a charged particle moving through a potential difference is given by

\Delta U = q \Delta V

where

q is the magnitude of the charge of the particle

\Delta V is the potential difference

In this problem:

- the charge of the particle is 3.00 elementary charges, so

q=3e=3\cdot 1.6\cdot 10^{-19} J=4.8\cdot 10^{-19}J

- the potential difference is

\Delta V=4.50 V

So, the change in electrical potential energy is

\Delta U=(1.6\cdot 10^{-19}C)(4.50 V)=7.2\cdot 10^{-19} J

7 0
4 years ago
Why can Muhammad exert a greater punching force with his bare fist than he can while wearing a
weqwewe [10]

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

5 0
3 years ago
Some giant ocean waves have a wavelength of 25 m and a frequency of
kolezko [41]

Answer:

Explanation:

The frequency equation for waves is

f=\frac{v}{\lambda} where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:

.26=\frac{v}{25} so

v = .26(25) and

v = 6.5 meters/second

3 0
3 years ago
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