1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivolga24 [154]
2 years ago
10

Suppose a car approaches a hill and has an initial speed of

Physics
1 answer:
kvv77 [185]2 years ago
5 0

Answer:

a) 1.73*10^5 J

b) 3645 N

Explanation:

106 km/h = 106 * 1000/3600 = 29.4 m/s

If KE = PE, then

mgh = 1/2mv²

gh = 1/2v²

h = v²/2g

h = 29.4² / 2 * 9.81

h = 864.36 / 19.62

h = 44.06 m

Loss of energy = mgΔh

E = 780 * 9.81 * (44.06 - 21.5)

E = 7651.8 * 22.56

E = 172624.6 J

Thus, the amount if energy lost is 1.73*10^5 J

Work done = Force * distance

Force = work done / distance

Force = 172624.6 / (21.5/sin27°)

Force = 172624.6 / 47.36

Force = 3645 N

You might be interested in
Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B
Slav-nsk [51]

The correct answer is

C. Light can pass through Object B faster than it can pass through Object A.

In fact, the index of refraction of a material is defined as:

n=\frac{c}{v}

where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:

v=\frac{c}{n}

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

4 0
3 years ago
Read 2 more answers
Which of the following forms of energy must an object have if it is moving at a constant velocity?
lbvjy [14]

Answer:

Kinetic energy

Explanation:

5 0
3 years ago
A jet can travel the 6000 km distance between washington,
Andrei [34K]
<span> d = r*t is the basic distance equation
 d = 6000 km
 t with the tail wind = 6 hr
 r with the tail wind = speed of the plane + wind speed = s + w
 t with the head wind = 7.5 hr
 r with the head wind = speed of the plane - wind speed = s-w
 (s+w)*6 = 6000
 (s-w)*7.5 = 6000
 s + w = 1000
 s - w = 800
</span><span> 2s = 1800
 s = 900 km/h
 s + w = 1000
 w = 100
 Check the anwer by calculating the return trip.
 (900-100) * 7.5 = 800 * 7.5
 800 * 7.5 = 6000 km
 Answer: The rate of the jet in still air is 900 km/h. The rate of the wind is 100 km/hr.</span>
6 0
2 years ago
The equation for density is mass divivded by volume.an increase in denstiy can result from all of following expect??
sineoko [7]
It would be option A (a decrease in mass with an increase in volume)
4 0
2 years ago
Which point on the diagram best represents the position of the Earth and the Sun
yanalaym [24]
I’m pretty sure point D cause North America is in the opposite direction of the sun
8 0
3 years ago
Read 2 more answers
Other questions:
  • El valor más preciso de la masa de un electron es 9.11*10^-11kg ¿ Cuánto aumentaría la masa de un cuerpo que se carga con -1 c d
    10·1 answer
  • Wind erosion can be reduced by _____.
    14·1 answer
  • Which two men developed the steam engine?
    10·1 answer
  • A quarterback claims that he can throw the football a horizontal distance of 167 m. Furthermore, he claims that he can do this b
    14·1 answer
  • PLS HELP I NEED THIS BY TODAY
    9·1 answer
  • What's inside a nucleus and makes RNA to make proteins
    7·1 answer
  • 22 POINTS!!PLEASE HELP
    7·1 answer
  • Four equal masses m are located at the corners of a square of side L, connected by essentially massless rods. Find the rotationa
    13·1 answer
  • A rocket fires its engines to launch straight up from rest with an upward acceleration of 5 m/s2 for 10 seconds. After this time
    11·2 answers
  • you showed me what true love is really like and made my confidence come back :) couldn't have asked for anything better!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!