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Inga [223]
3 years ago
14

If the runner completes exactly one lap what is her average speed? her average velocity? Explain your answer.

Physics
1 answer:
KIM [24]3 years ago
4 0

Average speed  =  (total distance covered) / (time to cover the distance).

Runner's average speed = (length of 1 lap) / (her time to run 1 lap).

________________________________

Average velocity =

           (straight-line distance between start-point and end-point)
divided by
           (time to go from start-point to end-point).

The runner's start-point and end-point are the same place.
The distance between them (her 'displacement') is zero. 
Her average velocity = zero .
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Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field
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Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength  at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength  at the midpoint between the two rings is given as;

E_{mid} = E_{right} +E_{left}\\\\E_{right}  = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt}  = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }  - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0

Therefore, the electric field strength at the mid-point between the two rings is zero.

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