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Inga [223]
3 years ago
14

If the runner completes exactly one lap what is her average speed? her average velocity? Explain your answer.

Physics
1 answer:
KIM [24]3 years ago
4 0

Average speed  =  (total distance covered) / (time to cover the distance).

Runner's average speed = (length of 1 lap) / (her time to run 1 lap).

________________________________

Average velocity =

           (straight-line distance between start-point and end-point)
divided by
           (time to go from start-point to end-point).

The runner's start-point and end-point are the same place.
The distance between them (her 'displacement') is zero. 
Her average velocity = zero .
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An aquarium 8 m long, 4 m wide, and 4 m deep is full of water. The hydrostatic pressure on the bottom of the aquarium is ____ Ne
MA_775_DIABLO [31]

Answer:

Explanation:

Given

length=8 m

width=4 m

deep=4 m

Area of base A=4\times 8=32 m^2

hydro static Pressure on bottom=\rho gh

P=10^3\times 9.8\times 4=39.2 kPa

Force on bottom=P\times A=1254.4 KN

Now pressure at the side wall

F=\rho gA \bar{x}

where \bar{x} is the mean length of wall = 4 m

F=10^3\times 9.8\times 4\times 8\times 2=627.2 KN

4 0
3 years ago
A particle of mass m moves under a conservative force with potential energy V ( x )= cx/(x2+a2),where c and a are positive const
Anvisha [2.4K]

Answer:

The position of stable equilibrium is -a

And the period of small oscillations  must be: c/(ma^3)

Explanation:

Since the potential is:

V(x) = \frac{c x}{a^2+x^2}

We first look for a position of stable equilibrium. This posiiton must satisfy two considtions, that the first derivative of the potential must vanish at this point and the second derivative must be positive.

V'(x) = \frac{c}{a^2+x^2}-\frac{2 c x^2}{\left(a^2+x^2\right)^2}

Which vanish for

x = a   ; x =-a

The second derivative of V(x) is:

V''(x) = \frac{8 c x^3}{\left(a^2+x^2\right)^3}-\frac{6 c x}{\left(a^2+x^2\right)^2}

And:

V''(a) = -\frac{c}{2 a^3}\\V''(-a) = \frac{c}{2 a^3}\\

Therefore:

a)

The position of stable equilibrium is -a

And the period of small oscillations  must be:

\omega = \sqrt{2 V''(-a)/m} = \sqrt{\frac{c}{a^3 m}}

(c/(ma^3))^1/2

b)

Let's find the maximum amplitude if the particle starts at this point with velocity v

If this is the case, the total energy will be:

(mv^2)/2

And the maximum amplitude will be

x = a^3/c mv^2 = (m v^2 a^3)/ c

7 0
3 years ago
Calculate the weight of the following:<br> a. A car with a mass of 2500kg
Alex Ar [27]

Answer:

24525 N

Explanation:

The <em>mass</em> of an object is a fundamental property of the object.

The <em>weight</em> of an object is the force of gravity on the object.

This is defined as follows

Weight (W)= mass(m) × weight of a unit mass(g)

( gravitational field intensity = g)

Assuming g= 9.81 ms⁻²,

   W = mg

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6 0
3 years ago
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Vladimir [108]

Answer:

There are three kinds of rock: igneous, sedimentary, and metamorphic.

7 0
3 years ago
What is the path of an electron moving perpendicular to a uniform magnetic field?
agasfer [191]
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Explanation:

this is your answer I hope it is helpful please mark me brainly

7 0
3 years ago
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