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3 years ago

Which of the following is a noncontact force? A. electrical forces B. gravitational forces C. magnetic forces D. all of these

Physics

2 answers:

Tamiku [17]3 years ago

7 0

Answer:

D. all of these

Explanation:

Electric forces, gravitational forces and magnetic forces are non contact forces. These forces are also the fundamental forces. Non contact forces are the forces which applied on a body without any real touch. Generally these non contact forces are in equilibrium.

goblinko [34]3 years ago

6 0

D. all of these

hope this helps.

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The two-second rule.

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The greater the mass is in an object, the higher resistance to a change in movement the object will have. Please select the best

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3 years ago

Energy input remains constant and voltage remains the same in a circuit, but current decreases. Which must be happening?

RUDIKE [14]

A) the resistance is increasing

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4 years ago

An object is dropped from the top of a building and is observed to take 7. 2s to hit the ground. How tall is the building?.

maw [93]

the height of the building is H=36 m.

<h3>What is The Law of Gravity?</h3>

According to Newton's law of gravity, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.

Properties of Gravity -

It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.
It obey inverse square law.
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The force that holds the gases in the sun.
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v₀=0 m/s

H₀=0 m

g=10 m/s²

t=7,2 s

H - ?

$H= H_{0} + v_{0}t+\frac{gt^{2} }{2} \\$

H = 0 +0 × 7.2 + 10(7.2)²/2

H = 36m

to learn more about Gravity go to - brainly.com/question/12528243

#SPJ4

8 0

2 years ago

Temperature change time base problem. Suppose V = 24 V, I = 0.1 A, for water: mw = 51 gm, cw = 4.18 J/gm ∘K-1, for resistor: mr

nirvana33 [79]

Answer:

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

I = 0.1 ampere

mass of water mw = 51 gm

cr = 4.18 J/gm degree K^-1

mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

so equating both side we have

$\frac{E}{t} = VI$

solving for t

$t = \frac{E}{VI}$

$t = \frac{m_w C_w \Delta T}{VI}$

$t = \frac{51 \times 4.18 \times (5 -0)}{24\times 0.1}$

t = 444.125 sec

5 0

4 years ago

Read 2 more answers