Suppose the ring rotates once every 4.30 s . If a rider's mass is 53.0 kg , with how much force does the ring push on her at the
1 answer:
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Answer:
Explanation:
Mathematically, linear momentum is expressed as the product of mass and velocity. Linear momentum conservation law states that a body or system of bodies retains its total momentum unless an external force is applied to the system.
In this case, the system consists of two carts.
At the start, the linear momentum (P) of the system is equal to:
It's only composed of linear momentum of the standard cart because cart A doesn't have any linear momentum at that moment.
After the collision, linear momentum has to be the same
where m_A is the mass of the cart A.
Solving for m_A
After the cart A rebounds, the linea momentum of the system has changed (because of the force present in the rebound). The new linear momentum is:
Then, the lump of putty is added to the system, but the linear momentum has to be the same, because we added a mass, not a force. The mass of that putty (m_p) has to be added to the equation of the system
Solving for m_p
Answer:
Tangential speed = 5.72 m/s
Centripetal acceleration =
Explanation:
The tangential speed, V, is given by
where is the angular speed and is given by
(f is the angular frequency or frequency of rotation)
Thus,
The centripetal acceleration,a, is given by