First right is brainliest, plz help:)

A merry go round exerts a force of 1000 N on a rider on the

SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

$F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r$

Where;

m = The mass of the person

v = The velocity of the person

$F_c$ = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for the centripetal force, we have;

$F_c$ = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0

3 years ago

Alice's friends Bob and Charlie are having a race to a distant star 10 light years away. Alice is the race official who stays on

hodyreva [135]

Solution :

The distance between the starting point and the end point, $L_0$ = 10 light years

But due to the relativistic motion of Bob and Charlie, the distance will be reduced following the Lorentz contraction. The contracted length will be different since they are moving with different speeds.

For Bob,

Speed of Bob's rocket with respect to Alice, $L_b = 0.7 \ c$

So the distance appeared to Bob due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_b^2}{c^2}$

$L_b=10\times \sqrt{1-0.49} \ Ly$

$=7.1 \ Ly$

Therefore, the time required to finish the race by Bob is

$t_b = \frac{L_b}{V_b}$

$=\frac{7.1 \ c}{0.7 \ c}$

= 10.143 year

For Charlie,

Speed of Charlie's rocket with respect to Alice, $L_c = 0.866 \ c$

So the distance appeared to Charlie due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_c^2}{c^2}$

$L_b=10\times \sqrt{1-0.75} \ Ly$

$=5 \ Ly$

The time required to finish the race by Charlie is

$t_b = \frac{L_c}{V_c}$

$=\frac{5 \ c}{0.866 \ c}$

= 5.77 year

5 0

3 years ago

The relationship between electricity and magnetism is called what

Leno4ka [110]

The relationship between electricity and magnetism is called<span> electromagnetism.</span>

5 0

3 years ago

A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu

Oduvanchick [21]

Answer:

It's Momentum becomes 4

4 0

4 years ago

What is damping??????

Marianna [84]

An influence upon an oscillatory system that has the effect of reducing/restriction or preventing its oscillations. Damping is produced by processes that dissipate the energy stored in the oscillation.

7 0

3 years ago

Read 2 more answers