Half-life of a radioactive substance is the time required to reduce the amount of substance to half of its initial amount.
In present case, half-life is material is given as 1000 years and initial amount of material is given as 400 kg
Answer 1) Since, half-life of radio-active substance is 1000 years, therefore after 1st half life, amount of the material will be left to half the initial amount. Hence, amount of substance left after 1000 years = 400/2 = 200 kg.
Answer 2) For 2000 years, radioactive material has crossed 2 times the half life. Therefore , amount of the material will be left to 1/4 the initial amount. Hence, amount of substance left after 2000 years = 400/4 = 100 kg.
Answer 3) For 4000 years, radioactive material has crossed 4 times the half life. Therefore , amount of the material will be left to 1/16 the initial amount. Hence, amount of substance left after 4000 years = 400/16 = 25 kg.
Answer
63.55
Explanation:
63
C
u
has
69.2
%
abundance.
65
C
u
has
30.8
%
abundance.
So, the weighted average is
62.93
×
69.2
%
+
64.93
×
30.8
%
I think C and D is correct
<u>Answer:</u>
The disposal method used for high-level nuclear waste Concentrate and contain
<u>Explanation:</u>
High intensity nuclear waste is an underlying issue for the world where the generated nuclear waste is one side very hazardous and on other side would help us in many viable processes but the negative sides of a consequence just outnumber the positive sides of the situation.
Concentrate and contain is a waste disposable method which enables the nuclear waste to be preserved and isolated and later be used when the time comes. Other methods would not be suggested because they could cause a huge amount of dangerous radioactivity in oceans which is often harmful for people.
Answer:
Kc = 9.52.
Explanation:
<em>A + 2B ⇌ C,</em>
Kc = [C]/[A][B]²,
Concentration: [A] [B] [C]
At start: 0.3 M 1.05 M 0.55 M
At equilibrium: 0.3 - x 1.05 - 2x 0.55 + x
0.14 M 1.05 - 2x 0.71 M
- For the concentration of [A]:
∵ 0.3 M - x = 0.14 M.
∴ x = 0.3 M - 0.14 M = 0.16 M.
∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.
<em>∵ Kc = [C]/[A][B]²</em>
∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.