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kramer
3 years ago
8

Two of the simplest compounds containing just carbon and hydrogen are methane and ethane. Methane contains 0.3357 g of hydrogen

for every 1.00 g of carbon. The ratio of grams of hydrogen per gram of carbon in methane to grams of hydrogen per gram of carbon in ethane is 4:3. Determine the number of grams of hydrogen per gram of carbon in ethane.
Chemistry
1 answer:
Andreyy893 years ago
5 0
Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g

Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:

M / E = 4/3

If we cross multiply,

3M = 4E

Now, substituting the value of M from earlier and solving for E,

E = (3 * 0.3357) / 4
E = 0.2518

There are 0.2518 grams of hydrogen per gram of carbon in ethane.
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The movement of cold, nutrient-rich water from the deep ocean to the ocean surface is known as?​
mylen [45]

Answer:

Upwelling! Its the process where the deep cold water rises to the surface! :)

Explanation:

Hope this helps! :)

5 0
3 years ago
Describe the five steps to the procedure called elemental analysis.
alexdok [17]

Answer:

on the successful completion of a number of different steps: planning (identifying the most appropriate analytical procedure), sample selection, sample preparation, performance of analytical procedure, statistical analysis

Explanation:

hope it helps

4 0
3 years ago
476 nm = 4.76x10^[?] cm
Stolb23 [73]

Answer:

4.76×10¯⁵ cm

Explanation:

We'll begin by converting 476 nm to m. This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

476 nm = 476 nm × 1×10¯⁹ m / 1 nm

476 nm = 4.76×10¯⁷ m

Finally, we shall convert 4.76×10¯⁷ m to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

4.76×10¯⁷ m = 4.76×10¯⁷ m × 100 cm / 1 m

4.76×10¯⁷ m = 4.76×10¯⁵ cm

Thus,

476 nm = 4.76×10¯⁵ cm

4 0
3 years ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?
Ad libitum [116K]

You're looking for the number of moles of H2, and you have 6.0 mol Al and 13 mol HCL.

For the first part, you have to make your way from 6.0 mol of Al to mol of H2, right? For that to happen, you need to make a conversion factor that will cancel the mol Al, in such case use the 2 moles of Al from your equation to cancel them out. At the top of the equation, you can use the number of moles of H2 from the equation and find the moles that will be produced for the H2.

6.0mol Al x 3 mol H2/2 mol Al = 9 mol H2

For the second part, you have to make the same procedure, make a conversion factor that will cancel the mol of HCL and for that you need to use the 6 mol HCL from your equation, and at the numerator you can put the 3 mol of H2 from the equation so that you can find the number of moles of H2 that will be produced.

13 mol HCL x 3 mol H2/6 mol HCL = 6.5 mol H2

As it can be seen, HCL produces the less amount of H2 moles. Therefore, the reaction CANNOT produce more than 6.5 mol H2, in that case 6.5 mol will be the maximum number of moles that will be produced at the end because HCL does not have enough to produce more than 6.5 mol.

In that case HCL is the limiting reactant because it limits that will be produced, and so the answer is B!

6 0
3 years ago
Is there any evidence that methanol forms ions either in the pure state or when dissolved in water?
worty [1.4K]
According to research, the answer is no. Although alcohol is dissolves in water solution but dissociation of methyl alcohol in into ions is barely not possible. Thus, methanol is considered as a non-electrolyte.
3 0
3 years ago
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