Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,

Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 %
</u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
Answer:
z≅3
Atomic number is 3, So ion is Lithium ion (
)
Explanation:
First of all
v=f*λ
In our case v=c
c=f*λ
λ=c/f
where:
c is the speed of light
f is the frequency

Using Rydberg's Formula:

Where:
R is Rydberg constant=
z is atomic Number
For highest Energy:
n_1=1
n_2=∞

z≅3
Atomic number is 3, So ion is Lithium ion (
)
They added tubes thats the answer
Answer:
electrophilic addition
Explanation:
CH3 - CH = CH2 + Cl-Cl ---> CH3 -CH(Cl) - CH2(Cl)
169.32 grams of NH3 ........