Answer:
The required volume of the original sample required is 2 micro liter
Explanation:
assuming the original sample concentration is 1N
after final dilution of 10-2 solution concentration becomes 0.01 N
normality of original sample = 1 N
normality of final solution = 0.01 N
volume of original sample= ?
volume of final solution = 0.2 mL
Considering thef formula below :
N1V1 = N2V2
V1 = (N2V2)/N1
= (0.01*0.2)/1
= 0.002 mL
1 milli liter = 1000 micro liter
0.002 mL = 2 micro liter
The original sample required is 2 micro liter
