Question

How many moles of O2 are required to react with 6.6 moles of H2?

Answer 1

Answer:

For 1: 3.3 moles of oxygen gas is required.

For 2: 14 moles of hydrogen gas is required.

For 3: 1.5 moles of oxygen gas is required.

Explanation:

The chemical reaction of oxygen and hydrogen to form water follows:

$O_2+2H_2\rightarrow 2H_2O$

• For 1: When 6.6 moles of $H_2$ is reacted.

By Stoichiometry of the above reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas.

So, 6.6 moles of hydrogen gas will react with = $\frac{1}{2}\times 6.6=3.3mol$ of oxygen gas.

Hence, 3.3 moles of oxygen gas is required.

• For 2: When 7.0 moles of $O_2$ is reacted.

By Stoichiometry of the above reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas.

So, 7 moles of oxygen gas will react with = $\frac{2}{1}\times 7=14mol$ of hydrogen gas.

Hence, 14 moles of hydrogen gas is required.

• For 3: When 3.0 moles of $H_2O$ is formed.

By Stoichiometry of the above reaction:

2 moles of water is formed from 1 mole of oxygen gas.

So, 3.0 moles of water will be formed from = $\frac{1}{2}\times 3.0=1.5mol$ of oxygen gas.

Hence, 1.5 moles of oxygen gas is required.