Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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Complementary angles add up to 90°
∠BDC + ∠CDA = 90°
Answer: ∠BDC
Answer:
<u>60+14.35=88.27</u>
Step-by-step explanation:
5x12 for the rectangle on the right, then for the circle, using the formula A=πr², I get 28.27, which you divide by 2 because you only need half of the circle, and you get 88.27. I calculated the radius by subtracting 12-6 and then dividing that in half because the radius is half of the distance to the other end of the circle. Then you get the radius of 3, then plug it into the formula to get π(3)², which is just 3.14(9), and you get 28.27.
Answer:
3.5km
Step-by-step explanation:
not sure but this is how I'll do it tho
distance= 7 x 1/2 = 3.5 (km)
A. g(10)= -29
b.f(3)=16
c.h(-2)=-6
d.j(7)=23
e.h(a)=12/a
f. g(b+c)=-3b-3c+1 ...etc I'm bored