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2 years ago

10

ASAP, PLEASE!! Is the system of equations consistent and independent, consistent and dependent, or inconsistent? y = -3x + 1...

2y = -6x +2.
A. Consistent and independent

B. Consistent and dependent

C. Inconsistent

1 answer:

Aliun [14]2 years ago

7 0

I think this system is consistent and dependent

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high contrast toggle How many window coverings are necessary to span 50 windows if each window covering is 15 windows long?

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We know that
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it will take -------> 50/15=3.33 windows coverings
</span>So,
you need more than 3 coverings,
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the answer is
4 window coverings

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2 years ago

A company introduced a much smaller variant of its tablet, known as the tablet junior. Weighing less than 11 ounces, it was abou

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Answer:

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Step-by-step explanation:

Given that a company introduced a much smaller variant of its tablet, known as the tablet junior.

The weight was less than 11 oz. i.e. 50% lighter than std.

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the probability that the battery life for a tablet junior will be 9.5 hours or less

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2 years ago

Tyrek wants to lower his credit card debt and has been tracking his expenses for the past month. He found his variable expenses

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2 years ago

What is the slope of a line that passes through points (-1, 4) and (4, 9)?

Ede4ka [16]

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2 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

7 0

2 years ago