Answer:
Explanation:
Force between two charges is given by the following expression
F =
Q₁ and Q₂ are two charges and d is distance between two.
.1 = 
If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.
Force F = .3 N
If charge becomes one fourth , force also becomes one fourth .
F= 
= .025 N.
Reflection. It occurs when a wave bounces from the surface of an obstacle
Answer:
The value of the power is 
Explanation:
From the question we are told that
The power rating 
The frequency is 
The frequency at which the sound intensity decreases 
The decrease in intensity is by 
Generally the initial intensity of the speaker is mathematically represented as
![\beta_1 = 10 log_{10} [\frac{P_b}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_1%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D)
Generally the intensity of the speaker after it has been decreased is
![\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_2%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D)
So
![\beta_1-\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_1-%5Cbeta_2%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D-%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D)
=> ![\beta = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D-%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D%3D%201.3)
=> ![\beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D10log_%7B10%7D%20%5B%5Cfrac%7B%5Cfrac%7BP_b%7D%7BP_a%7D%7D%7B%5Cfrac%7BP_c%7D%7BP_a%7D%7D%20%5D%20%3D%201.3)
=> ![\beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D10log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%201.3)
=> ![10log_{10} [\frac{P_b}{P_c} ] = 1.3](https://tex.z-dn.net/?f=10log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%201.3)
=> ![log_{10} [\frac{P_b}{P_c} ] = 0.13](https://tex.z-dn.net/?f=log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%200.13)
taking atilog of both sides
=>
=> 
=> 
Answer:
q=6.22*10^-10C
Explanation:
Two large metal plates of area 0.88 m2 face each other, 4.8 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 80 N/C. Find |q|
E=α/∈, electric field within the plate
α=q/A
A=area of the plate
∈=is the permittivity
substituting , we have
The field magnitude E between them (neglect fringing)
E=q/A∈
q=EA∈
q=0.88*80*8.84*10^-12
q=6.22*10^-10C
Answer:
The volume of the cylinder is 
Explanation:
Given that,
The height of the cylinder is 13 cm
Radius of the cylinder is 4 cm
We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

So, the volume of the cylinder is 