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nataly862011 [7]
3 years ago
10

Helicopter blades withstand tremendous stresses. In addition to supporting the weight of a helicopter, they are spun at rapid ra

tes and experience large centripetal accelerations, especially at the tip. Calculate the centripetal acceleration at the tip of a 4.20 m long helicopter blade that rotates at 270 rev/min.
Compare the linear speed of the tip with the speed of sound (taken to be 340 m/s), i.e., calculate the ratio of the linear speed over speed of sound.
Physics
1 answer:
ella [17]3 years ago
6 0
A.) 
<span>(Centripetal Acceleration) = (radius)*(angular velocity)^2 </span>
<span>325 rev/min = 34.0339204 radians/second </span>
<span>(Centripetal Acceleration) = (4.00 m)*(34.0339204 radians/second)^2 </span>
<span>(Centripetal Acceleration) = 4 633.23095 meters/second^2 </span>

<span>b.) </span>
<span>(tangential velocity) = sqrt((centripetal acceleration)*(radius)) </span>
<span>just plug them in and get a velocity, then divide that by 340 m/s to get your percentage of the speed of sound, so if you get for example 680, that would be twice the speed of sound or Mach 2</span>
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Explanation:

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Answer:

The  value of the power is   P_c  =  38.55 \  W

Explanation:

From the question we are told that

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Generally the  initial intensity of the speaker  is mathematically represented as

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Generally the intensity of the speaker after it has been decreased is

       \beta_2 =  10 log_{10} [\frac{P_c}{P_a} ]

So

\beta_1-\beta_2 =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]

=>  \beta =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3

=>  \beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3

=>  \beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3

=> 10log_{10} [\frac{P_b}{P_c} ] = 1.3

=> log_{10} [\frac{P_b}{P_c} ] = 0.13

taking atilog of both sides

[\frac{P_b}{P_c} ] = 10^{0.13}      

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=>  P_c  =  \frac{52}{1.34896}

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Answer:

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