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KengaRu [80]
4 years ago
8

When a compass needle settles down in a magnetic field, _______. the needle aligns itself with the field, the south end of the c

ompass needle pointing in the direction of the field the axis of the needle is perpendicular to the field the needle aligns itself with the field, the north end of the compass needle pointing in the direction of the field where the needle points depends upon how the compass case is oriented

Physics
1 answer:
Rus_ich [418]4 years ago
7 0

Answer:

The needle aligns itself with the field, the north end of the compass needle pointing in the direction of the field.

Explanation:

When the current flows through the coil, magnetic field is generated. When the compass is placed in the field, the needle aligns itself along the field. The north of the compass points in the direction of the field.

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A compound is a substance that consists of two or more elements, which is chemically combined, meaning that it could only be split by chemical means. 

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Two cars with the same velocity must have the same speed. True or false ?
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Find the length of each vector below.
Leona [35]

Answer:

a. 3.6 units

b. 1.4 units

c. 3.6 units

d. 6.1 units

Explanation:

The length of a vector is given by the following formula:

Length = √(x² + y²)

where,

x = x-component of vector

y = y-component of vector

a.

Here,

x = 2

y = 3

Therefore,

Length = √(2² + 3²)

Length = √13

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b.

Here,

x = 1

y = 1

Therefore,

Length = √(1² + 1²)

Length = √2

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c.

Here,

x = 2

y = -3

Therefore,

Length = √(2² + (-3)²)

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d.

Here,

x = 1

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8 0
3 years ago
At the local swimming pool, the diving board is elevated h = 8.5 m above the pool surface and overhangs the pool edge by L = 2 m
Tasya [4]

Answer:

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t_w = \sqrt{\frac{2h}{g}}

Part b)

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Part c)

d_w = 6.88 m

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Part a)

As we know that the diver will have zero velocity in vertical direction

so here we can say that

\Delta y = v_y t + \frac{1}{2}a_y t^2

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t_w = \sqrt{\frac{2h}{g}}

Part b)

as we know that

h = 8.5 m

g = 9.81 m/s^2

so we will have

t_w = \sqrt{\frac{2(8.5)}{9.81}}

t_w = 1.32 s

Part c)

Distance covered by diver from the edge of the pool is given as

d_w = L + v_w t_w

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Explanation:

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