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gogolik [260]
3 years ago
8

Look at the divisions between 2 and 4. What level of precision does this stopwatch have based on the divisions marked on its fac

e?
Physics
1 answer:
klemol [59]3 years ago
8 0

Answer:

10ths of a second

Explanation:

Because I just did it

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Consider the addition of an electron to the following atoms from the third period. Rank the atoms in order from the most negativ
sergeinik [125]

The question is incomplete, the atoms in the third period referred to in the question are shown in the image attached.

Answer:

Cl>Si>Ar

Explanation:

Electron affinity refers to the energy released when an atom accepts electron (s) to form a negative ion. It is a periodic property that shows similar trends as electro negativity.

Considering the atoms in period three given in the question; chlorine will have the most negative value of electron affinity. This owes to the fact that halogens accept electrons easily to form negative ions. Silicon in group 14 shows much less negative value of electron affinity while argon, a noble gas, does not accept electrons at all and has an electron affinity of zero KJMol-1 by standard.

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4 years ago
Learning Goal: To practice Problem-Solving Strategy 19.1 Work in Ideal-gas Processes. A cylinder with initial volume VVV contain
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Answer:

The work done on the gas is equal to the area under the curve pv diagram w = area of triangle = 1/2 (base)(height) = 1/2 (BC)(Ac) = 1/2 (3v - v)(3p - p) = 1/2 (9 vp - 3 vp - 3vp + vp) = 4 vp/2 W = 2 vp

Check attachment for the diagrammatic representation

5 0
4 years ago
State keplers law........​
S_A_V [24]

Answer:

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its

4 0
3 years ago
The voltage between the cathode and the screen of a television set is 22 kV. If we assume a speed of zero for an electron as it
il63 [147K]

Answer:

v= 8.8*10⁷ m/s

Explanation:

  • Assuming no friction present, the change in electrical potential energy, must be equal in magnitude, to the change in kinetic energy of the electron.
  • The change in the electrical potential energy, can be expressed as follows:

       \Delta U = (-e)*\Delta V

  • The change in kinetic energy, assuming that the electron started from rest, can be written as follows:

       \Delta K = \frac{1}{2} *m*v^{2}

       ⇒\Delta K = -\Delta U

  • From the equation above, replacing by ΔK and ΔU, we have:

       -\Delta U =- (-e)*\Delta V =\Delta K = \frac{1}{2} *m*v^{2}

  • Solving for v:

        v=\sqrt{\frac{2*e*\Delta V}{m_{e}} } =\sqrt{\frac{2*1.6e-19C*22e3V}{9.1e-31kg}} }\\ v= 8.8e7 m/s

4 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl
aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i:  unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R=  131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2}  }

D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2}  }

D₂= 167.21 cm

Direction of the second displacement

\beta = tan^{-1} \frac{D_{y}}{D_{x} }

\beta = tan^{-1} \frac{62.18}{155.22 }

β= 21.8°

D₂= 167,21 cm : Magnitude  of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0
4 years ago
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