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3 years ago

8

Look at the divisions between 2 and 4. What level of precision does this stopwatch have based on the divisions marked on its fac

e?

1 answer:

klemol [59]3 years ago

8 0

Answer:

10ths of a second

Explanation:

Because I just did it

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Find the force, in Newtons, on a rectangular metal plate with dimensions of 4 m by 8 m that is submerged horizontally in 9 m of

Irina18 [472]

Answer:

$F \approx 3*10^6$

Explanation:

From the question we are told that:

Dimension of plate: $4 m by 8 m$

Depth submerged $d=9m$

Water density $\rho=1000 kg/m3$

Gravity $g=9.8m/s^2$

Generally the equation for Volume is mathematically given by

$V=L*B*d$

$V=4*8*9$

$V=288$

Therefore The mass of Plate is

$m=\rho*V$

$m=1000*288$

$m=288000kg$

Generally the equation for Force on the plate is mathematically given by

F=ma

$F=288000*9.8$

$F=2822400N$

$F=2.8*10^6$

$F \approx 3*10^6$

4 0

3 years ago

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys

son4ous [18]

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

$\Delta U =U_f - U_i =Q-W$

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

$U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J$

3 0

3 years ago

Cooling down after a workout allows the oxygen to continuing moving through the body and keeps the muscles from tightening up to

Liono4ka [1.6K]

Answer: true

Explanation:

7 0

3 years ago

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joja [24]

B is the answer...

mark brainliest

3 0

3 years ago

An object of irregular shape has a characteristic length of L = 0.5 m and is maintained at a uniform surface temperature of Ts =

goblinko [34]

Answer:

The value of the average convection coefficient is 20 W/Km².

Explanation:

Given that,

For first object,

Characteristic length = 0.5 m

Surface temperature = 400 K

Atmospheric temperature = 300 K

Velocity = 25 m/s

Air velocity = 5 m/s

Characteristic length of second object = 2.5 m

We have same shape and density of both objects so the reynold number will be same,

We need to calculate the value of the average convection coefficient

Using formula of reynold number for both objects

$R_{1}=R_{2}$

$\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}$

$\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}$

Here, $k_{1}=k_{2}$

$h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}$

$h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}$

Put the value into the formula

$h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}$

$h_{2}=20\ W/Km^2$

Hence, The value of the average convection coefficient is 20 W/Km².

7 0

3 years ago