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gogolik [260]
3 years ago
8

Look at the divisions between 2 and 4. What level of precision does this stopwatch have based on the divisions marked on its fac

e?
Physics
1 answer:
klemol [59]3 years ago
8 0

Answer:

10ths of a second

Explanation:

Because I just did it

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Answer:  Frequency factor  A = 8 × 10⁹

activation energy Ea = 15.5 KJ/Mol

Explanation: to begin, let us first define the parameters given;

K₁ = 1.44 × 10⁷dm³mol⁻¹s⁻¹

K₂ = 3.03 × 10⁷ dm³mol⁻¹s⁻¹

K₃ = 6.9 × 10 dm³mol⁻¹s⁻¹

also T₁ = 300.3 K

T₂ = 341.2 K

T₃ = 392.2 K

we know that;

㏑ K₂ / K₁ = Ea/R [1/T₁ -1/T₂]

where R is given as 8.314 J/mol-k

Ea = activation energy

K₁, K₂ = rate constant

T₁, T₂ = Temperature

therefore, ㏑ (3.03 × 10⁷/ 1.44 × 10⁷) = Ea / 8.314 [1/300.3 - 1/341.2]

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also given that K = A e⁻∧Ea/RT

here A = frequency factor

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A = 7.99 × 10⁹ = 8 × 10⁹

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