Given values:
Mass of the steel ball, m = 100 g = 0.1 kg
Height of the steel ball, h1 = 1.8 m
Rebound height, h2 = 1.25 m
a. PE= mgh
0.1 x 9.8 x 1.8 =
1.764 Joules
b. KE = PE ->
1.764 Joules
c. KE= 1/2 mv square
so v = square root 2ke/m
square root 2 x 1.764/ 0.1
= 5.93 m/s
d. KE=PE=mgh square
0.1 x 9.8 x 1.21 =
1.186 joules
velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s
Because you see yourself the opposite way in a mirror. So yes your “seeing” yourself but not how everyone else sees you.
Amman oak smoke skins kaons
Answer:
0.9999986*c
Explanation:
The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

Where
Δt is the travel time as seen by a passenger
Δt' is the travel time as seen by someone on Earth
v is the speed of the ship
c is the speed of light in vacuum
We can replace the fraction v/c with x






It would need to travel at 0.9999986*c