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Kazeer [188]
3 years ago
10

Find the common difference of the sequence shown. 1/6, 1/3, 1/2 , 2

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

1/6

Step-by-step explanation:

sequence should be 1/6,1/3,1/2,2/3

common difference=1/3-1/6=2/6-1/6=1/6

or 1/2-1/3=(3-2)/6=1/6

or c.d.=2/3-1/2=(4-3)/6=1/6

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Answer/Step-by-step Explanation:

1. 3x - 10 +4 if x = 3

To evaluate, plug in the value of x in the expression given

3(3) - 10 + 4 = 9 - 10 + 4

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2. \frac{x}{2} + 6x

if x = -12

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3. 8(x - y), if x = 2, y = 6

8(2 - 6) = 8(-4) = -32

4. x + xy, if x = 3, y = -2.5

3 + (3)(-2.5) = 3 + (-7.5)

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= 16 + 6 = 22

6. 3x + 4y - 3x, if x = 2, y = 4

3(2) + 4(4) - 3(2) = 6 + 16 - 6

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7. -10x + \frac{4}{x}

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8. 3(8x - 10) + 5x, if x = ½

3(8*½ - 10) + 5(½)

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9. x + 8y - (x)², if x = -5, y = ¼

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10. (8x)² + 6x + 2, if x = -3

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= 576 - 18 + 2 = 560

11. 2x² + 4y² + xy, if x = ½, y = 2

2(½)² + 4(2)² + (½)(2)

= 2(¼) + 4(4) + 1

= ½ + 16 + 1 = ½ + 17 = 17½

12. 8x + 2y, if x = 1.5, y = -2.2

8(1.5) + 2(-2.2)

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13. \frac{5}{2}(x - 6) + 4

if x = 8.

\frac{5}{2}(8 - 6) + 4

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Answer:

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Based on this definition if a function, the functions y = x², y = -x and y = x are all functions because for any value of x imputed in them, we can only get one equivalent value of y.

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