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SpyIntel [72]
3 years ago
7

Mechanics is the study of

Physics
1 answer:
svetoff [14.1K]3 years ago
4 0
Mechanics is the study of motion and force on physical objects and their surroundings
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A 16.0 kg crate rests on a shelf 1.80 m above the floor in a warehouse. A forklift is used to raise the crate to a shelf 3.30 m
klio [65]

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

<h3>What is potential energy?</h3>

It is the energy due to the position.

A 16.0 kg (m) crate rests on a shelf 1.80 m (h₁) above the floor in a warehouse. The potential energy is:

U₁ = m × g × h₁ = 16.0 kg × (9.81 m/s²) × 1.80 m = 283 J

A forklift is used to raise the crate to a shelf 3.30 m (h₂) above the warehouse floor. The potential energy is:

U₂ = m × g × h₂ = 16.0 kg × (9.81 m/s²) × 3.30 m = 518 J

The increase in the potential energy is:

518 J - 283 J = 235 J ≈ 240 J

A 16.0 kg crate increases in height from 1.80 m to 3.30 m above the floor. The increase in potential energy is 240 J (a).

Learn more about potential energy here: brainly.com/question/23979653

#SPJ1

5 0
2 years ago
A 2-kW electric heater takes 15 min to boil a quantity of water. If this is done once a day and power costs 10 cents per kWh, wh
frozen [14]

Answer:

<h2> $1.50</h2>

Explanation:

Given data

power P= 2 kW

time t= 15 min to hours = 15/60= 1/4 h

cost of power consumption per kWh= 10 cent = $0.1

We are expected to compute the cost of operating the heater for 30 days

but let us computer the energy consumption for one day

Energy of heater  for one day= 2* 1/4 = 0.5 kWh

the cost of operating the heater for 30 days= 0.5*0.1*30= $1.50

<u><em>Hence it will cost  $1.50 for 30 days operation</em></u>

4 0
3 years ago
A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

117.6 Joules

<h3>Explanation:</h3>

<u>We are given;</u>

  • Force of the dog is 24 N
  • Distance upward is 4.9 m

We are required to calculate the work done

  • Work done is the product of force and distance
  • That is; Work done = Force × distance
  • It is measured in Joules.

In this case;

Force applied is equivalent to the weight of the dog.

Work done = 24 N × 4.9 m

                  = 117.6 Joules

Hence, the work done in lifting the dog is 117.6 Joules

3 0
3 years ago
Consider the two electron arrangements for neutral atoms a and b. Are atoms a and b the same element? a - 1s2, 2s2, 2p6, 3s1 b -
Agata [3.3K]

The two neutral atoms A and B have the same number of electrons and atomic number 11. So, the two elements are said to be same.

The electronic configuration of the element is the arrangement of the electrons in the atom of the element in energy levels, orbitals around the nucleus.

The electrons in the atoms of the element with lowest energy are written first before those with higher energy levels. Thus, the electronic configuration shows the electrons in the atoms of the element arranged in order of increasing energies.

The electronic configuration of atoms are given as

A = 1s² 2s² 2p⁶ 3s¹

B = 1s² 2s² 2p⁶ 5s¹

The number of electrons in both the elements is 11. Therefore, their atomic number is also the same i.e, 11. So, both the elements are the same.

To know more about atomic number:

brainly.com/question/8645622

#SPJ4

4 0
2 years ago
A typical AA size rechargeable NiMH battery can store 1100-2100 mAh of electric charge. The small print on the battery in your h
Anni [7]

Answer:

The electric charge, q (in coulomb units) = 5004 C  

Given:

The charge stored as printed on NiMH battery, q = 1390 mAh  

Solution:

To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:

1 mA = 1\times 10^{-3}

1 hour = 60\times 60 = 3600 s

Also, we know that the rate of flow of charge is electric current, I:

I = \frac{q}{t}

⇒ q = [tex]I\times t[tex]                                   (1)

where

q = electric charge

I = current

t = time taken for flow of current

Using eqn(1), we get:

q = [tex]1390\times 10^{-3}\times 60\times 60[tex]

q = 5004 A-s = 5004 C

8 0
3 years ago
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