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3241004551 [841]
3 years ago
11

a sleepy atudent drops a calculator out of a window yhata 20.7 m off the geound. we can ignore air resistance. what js the veloc

ity of the calculator after falling for 1.8 s
Physics
1 answer:
frez [133]3 years ago
6 0

The acceleration of gravity is

9.8 m/s^2 down.

When an object falls out of a hand, its speed after 1.8s is

(9.8)x(1.8) = 17.6 m/s down.

It doesn't matter what it is, how much it weighs, or how high it was dropped from.

If it's more than 17.6 m/s, then this happened on a different, bigger planet.

If it's less than 17.6 m/s, then it must have hit something on the way down, like some air or something.

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Anaerobic metabolism:
goblinko [34]

Explanation:

B. leads to muscle strain.

5 0
3 years ago
A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts
Juli2301 [7.4K]

Answer:

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

        Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

7 0
3 years ago
A 3 μf capacitor is connected to a 6 v battery. what is the charge on each plate of the capacitor?
Lapatulllka [165]
C = 3 uf = 3 × 10^(-6) f
v = 6volts
Q = C.v
 = <span>3 × 10^(-6) </span>× 6
 = 18 × 10^(-6)
 = 1.8 = 10^(-5)
5 0
3 years ago
Three liquids that do not mix are poured into a cylindrical container with a diameter of 10.0 cm. The densities and volumes of t
kipiarov [429]

Answer:

P = 9622.9 Pa = 9.62 KPa

Explanation:

First, we will calculate the mass of all three liquids:

m = ρV

where,

m = mass of liquid

ρ = density of liquid

V = Volume of liquid

FOR LIQUID 1:

m₁ = (2.8 x 10³ kg/m³)(2 x 10⁻³ m³) = 5.6 kg

m₂ = (1 x 10³ kg/m³)(1.5 x 10⁻³ m³) = 1.5 kg

m₃ = (0.6 x 10³ kg/m³)(1 x 10⁻³ m³) = 0.6 kg

The total mass will be:

m = m₁ + m₂+ m₃ = 5.6 kg + 1.5 kg + 0.6 kg

m = 7.7 kg

Hence, the weight of the liquids will be:

W = mg = (7.7 kg)(9.81 m/s²) = 75.54 N

Now, we calculate the base area:

A = πr² = π(0.05 m)²

A = 7.85 x 10⁻³ m²

Now the pressure will be given as:

P = \frac{F}{A}\\\\P = \frac{75.54\ N}{7.85\ x\ 10^{-3}\ m^2}

<u>P = 9622.9 Pa = 9.62 KPa</u>

5 0
3 years ago
A turntable that is initially at rest is set in motion with a constant angular acceleration α. What is the magnitude of the angu
bekas [8.4K]

Explanation:

If the turntable starts from rest and is set in motion with a constant angular acceleration α. Let \omega is the angular velocity of the turntable. We know that the rate of change of angular velocity is called the angular acceleration of an object. Its formula is given by :

\alpha =\dfrac{\omega_f-\omega_i}{t}

\alpha =\dfrac{\omega-0}{t}

\alpha =\dfrac{\omega}{t}

t=\dfrac{\omega}{\alpha }............(1)

Using second equation of kinematics as :

\theta=\omega_i t+\dfrac{1}{2}\alpha t^2

\theta=\dfrac{1}{2}\alpha t^2

Using equation (1) in above equation

\theta=\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }

In one revolution, \theta=4\pi (in 2 revolutions)

4\pi =\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }

\omega=\sqrt{8\pi \alpha}

\omega=2\sqrt{2\pi \alpha}

Hence, this is the required solution.

6 0
4 years ago
Read 2 more answers
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