Answer:
Conc. of acetic acid in vinegar = 0.573M
%(mass) of acetic acid = 3.40%
Explanation:
All working is shown in pic.
Answer:
1.07×10²¹ molecules are needed to sound the alarm
Explanation:
Let's convert the mass of CO to moles, to determine the amount of molecules.
0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles
Now we can determine the number of molecules with the NA
1 mol has 6.02×10²³ molecules
1.78×10⁻³ moles may have (1.78×10⁻³ . 6.02×10²³) / 1 = 1.07×10²¹ molecules
Answer:
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Explanation:
Answer: The Answer is 0.3.
Explanation: Solved in the attached picture.