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Ivanshal [37]
3 years ago
15

1 of 9

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0

Answer: 40 800‬

idk if it is the answer but i just times it

Step-by-step explanation:

ANTONII [103]3 years ago
3 0

Answer:

£22674.96

Step-by-step explanation:

Find principal by using the formula  

I=P⋅i⋅t  , where I is interest, P is total principal, i is rate of interest per year, and t is total time in years.

In this example I = $7509.14, i = 5% and t = 6 years

£6800= $7509.14

I=P.i.t

P=I/i.t

P=$7509.14/0.05.6= $25030.47= £22674.96

link to a calculator app that can do it for you:

https://www.mathportal.org/calculators/financial-calculators/simple-interest-calculator.php

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
What is the solution to the equation 4w=2/3?
nikdorinn [45]

Answer:

2/12

Step-by-step explanation:

4w=2/3

1/4(4w)=1/4 x 2/3

w=2/12

6 0
3 years ago
What is the value of 5-8×(7-15+8)
salantis [7]

Answer:

I'm pretty sure that the answer is 5. Correct me if i'm wrong

Step-by-step explanation:


6 0
2 years ago
Think about a six-sided die with each number, 1 through 6, appearing once on each die. Which of the following events is mutually
Svetllana [295]
C. Rolling a 3 or a factor of 6
8 0
3 years ago
Can someone help me? i dont understand 3
Helga [31]

Answer:

What to know about the lines is the exact point is 0 what you need to know to find that is answer 1,  2 and 3

Step-by-step explanation:

6 0
2 years ago
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