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3 years ago

Which element is capable of forming long chains by forming single, double, or triple bonds with itself?

Chemistry

2 answers:

Minchanka [31]3 years ago

7 0

The answer is carbon

gayaneshka [121]3 years ago

5 0

Catenation is the property by which it can make bonds with other carbon atoms to form long chains. Hence, carbon, with the least diffuse valence shell p orbital is capable of forming longer p-p sigma bonded chains of atoms than heavier elements which bond via higher valence shell orbitals.

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Vladimir79 [104]

Answer:

Option b.) Potassium ion, is written correctly.

Explanation:

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3 years ago

Which of the following BEST describes what DNA looks like?

Ghella [55]

Answer:

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3 years ago

What is a saturated solution that cannot dissolve any more solute because it is too concentrated?

Aleksandr-060686 [28]

Answer:

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3 years ago

Read 2 more answers

Which of the following would be expected to be good solvents for cyclopentane. Choose all that apply. toluene, CgH5CH3 cyclohexa

Alik [6]

Answer:

cyclohexane

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Hence , from the question ,

a good solvent for cyclopentane would be cyclohexane ,

since , both the compounds are non polar in nature , hence get solubilized ,

the other options mentioned are polar .

8 0

3 years ago

A constant-volume calorimeter was calibrated by carrying out a reaction known to release 3.50 kJ of heat in 0.200 L of solution

Dmitrij [34]

Answer:

The change in internal energy is - 1.19 kJ

Explanation:

Step 1: Data given

Heat released = 3.5 kJ

Volume calorimeter = 0.200 L

Heat release results in a 7.32 °C

Temperature rise for the next experiment = 2.49 °C

Step 2: Calculate Ccalorimeter

Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C

Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C

Step 3: Calculate energy released

Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ

Step 4: Calculate change in internal energy

ΔU = Q + W W = 0 (no expansion)

Qreac = -Qcal = - 1.19 kJ

ΔU = - 1.19 kJ

The change in internal energy is - 1.19 kJ

4 0

4 years ago