Which element is capable of forming long chains by forming single, double, or triple bonds with itself?
2 answers:
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Answer:
To the right
Explanation:
Step 1: Given data
- Partial pressure of PCl₅ (pPCl₅) = 0.548 atm
- Partial pressure of PCl₃ (pCl₃) = 0.780 atm
- Partial pressure of Cl₂ (pCl₂) = 0.780 atm
Step 2: Write the balanced equation
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
Step 3: Calculate the pressure reaction quotient
Step 4: Determine whether the reaction proceeds to the right or to the left as equilibrium is approached
Since <em>Qp < Kp</em>, the reaction will proceed to the right to attain the equilibrium.
Answer:
1) HCl contains the Cl^- which is a good nucleophile
2) 2-methyl-2- heptanol > 2-heptanol > 1-heptanol
3) see image attached
Explanation:
If the dehydration of alcohols is carried out using HCl, the chloride ion which is a good nucleophile will attack the substrate to yield an undesirable product.
The dehydration of alcohols is an E1 reaction. Recall that the ease of E1 reaction increases in the order 3°> 2°> 1°. Hence, 2-methyl-2- heptanol forms a tertiary carbocation intermediate during dehydration and has the greatest ease of dehydration.
The three products formed during the dehydration of 3,3-dimethyl-2-butanol are shown in the image attached. Two out of the three are formed by rearrangement reactions.
