Which element is capable of forming long chains by forming single, double, or triple bonds with itself?

Chemistry

2 answers:

Minchanka [31]3 years ago

7 0

The answer is carbon

gayaneshka [121]3 years ago

5 0

Catenation is the property by which it can make bonds with other carbon<span> atoms to form long chains. Hence, </span>carbon<span>, with the least diffuse valence shell p orbital is capable of forming longer p-p sigma bonded chains of atoms than heavier elements which bond via higher valence shell orbitals.</span>

You might be interested in

10. What base unit of measurement is common to all systems?

Lera25 [3.4K]

Answer:

The SI system , also called theatrics system, is used around the world

5 0

2 years ago

What are the names of the positive and negative electrodes of an electrolytic cell?

xz_007 [3.2K]

Answer:

the positive electrode is an anode, and the negative electrode is a cathode.

Explanation:

6 0

2 years ago

Match each of the following forms of sugar to its best description?

prohojiy [21]

Sucrose, a sweet, white crystalline substance, C12 H22 O11, OBTAINED CHIEFLY FROM THE JUICE OF THE SUGAR CANE AND SUGAR BEET, BUT ALSO PRESENT IN SORGHUM, THE sugar maple, some palms, and various other plants, and having extensive nutritional, pharmaceutical, and industrial uses; any of the class of carbohydrates to which this substance belongs, as glucose, levulose, and lactose.

5 0

3 years ago

If you collect 1.75 L of hydrogen gas during a lab experiment when the room temperature is 23oC and the barometric pressure is 1

ziro4ka [17]

Answer:

$n=0.0747mol$

Explanation:

Hello,

In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:

$PV=nRT$

Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:

$n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol$

Best regards.

8 0

3 years ago

Describe how Gregor mendel's methods helped endure the accuracy of his results

aliina [53]

Not sure good luck on finding someone too help you

7 0

3 years ago