<u>Answer:</u> The mass of acetic acid present in the vinegar sample is 0.370 grams
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of NaOH solution = 0.140 M
Volume of solution = 44.0 mL
Putting values in above equation, we get:
The chemical equation for the reaction of acetic acid and NaOH follows:
By Stoichiometry of the reaction:
1 mole of NaOH reacts with 1 mole of acetic acid
So, 0.00616 moles of NaOH will react with = of acetic acid
To calculate the number of moles, we use the equation:
Molar mass of acetic acid = 60 g/mol
Moles of acetic acid = 0.00616 moles
Putting values in above equation, we get:
Hence, the mass of acetic acid present in the vinegar sample is 0.370 grams