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enyata [817]
3 years ago
12

An airplane is flying at a constant velocity through the air. What is the relationship between the magnitudes of the four forces

shown in the diagram?
A. L = W; F < D
B. L = W; F = D
C. L = W = F = D
D. L = W; F > D

Physics
1 answer:
zalisa [80]3 years ago
5 0

Answer:

(B) L=W; F=D

Explanation:

Since the airplane's velocity is constant, the airplane is not accelerating in any direction. In absence of acceleration, all forces acting on the plane are balanced so that the net forces in the horizontal and the vertical directions are zero. Given the drawing, this implies that

Forward force = Drag force (F=D)

Weight = Lift (W=L)

which corresponds to option (B)

(it is not C because nothing in the text says that the vertical and horizontal components have to have same magnitude)

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Two point charges 3q and −8q (with q &gt; 0) are at x = 0 and x = L, respectively, and free to move. A third charge is placed so
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Answer:

Explanation:

The unknown charge can not remain in between the charge given because force on the middle charge will act in the same direction due to both the remaining charges.

So the unknown charge is somewhere on negative side of x axis . Its charge will be negative . Let it be - Q and let it be at distance - x on x axis.

force on it due to rest of the charges will be equal and opposite so

k3q Q / x² =k 8q Q / (L+x)²

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2√2 x = √3 (L+x)

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x = √3 L / (2√2 - √3 )

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force on it due to -Q and -8q will be equal

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Q = 8q  (x² / L²)

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