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grandymaker [24]
3 years ago
15

Which shows a decrease in fluid pressure? A. A fan is turned from high speed to low speed. B. Oxygen is compressed as it is put

into a pressurized tank. C. Water in a creek slows down as it enters a slow-moving river. D. A river speeds up when it moves into a narrower channel.
Physics
2 answers:
Volgvan3 years ago
8 0

Answer:

Option A.

A fan is turned from high speed to low speed.

Explanation:

It is important to note that air is also a fluid.

In a system, static pressure of air increases with the speed of rotation of the fan. This is because when the speed of the fan is increased, the force with which it is pushing the air molecules is increased. Since pressure is a relationship between force and area, the pressure of the air molecules will be increased.

Conversely, when the speed of the fan is reduced, the priming force on the air molecules will be reduced, hence the pressure of the air will drop.

This makes option A the correct option

Olegator [25]3 years ago
4 0

Answer:

A. A fan is turned from high speed to low speed.

Explanation:

Liquid and gas are fluids.

In the case of the fan, it requires an amount of pressure to blow air particles. The higher the pressure, the faster the rotation and the more the air particles will be blown .

This means the fan being turned from high to low speed indicates a reduction in the fluid pressure and amount of air particles blown. This validates option A.

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Two bumper cars move in a straight line with the following equations of motion: x1 = -4.0 m + (1.1 m/s )t x2 = 8.8 m + (-2.9 m/s
lawyer [7]

Answer:

3.2 seconds

Explanation:

When the cars collide, they have the same position.

x₁ = x₂

-4 + 1.1t = 8.8 − 2.9t

4t = 12.8

t = 3.2

5 0
3 years ago
An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the
garik1379 [7]

(a) 6.04 rev/s

The speed of the ball is given by:

v=\omega r

where

\omega is the angular speed

r is the distance of the ball from the centre of the circle

In situation 1), we have

\omega=8.13 rev/s \cdot 2\pi = 51.0 rad/s

r = 0.600 m

So the speed of the ball is

v=(51.0 rad/s)(0.600 m)=30.6 m/s

In situation 2), we have

\omega=6.04 rev/s \cdot 2\pi = 37.9 rad/s

r = 0.900 m

So the speed of the ball is

v=(37.9 rad/s)(0.900 m)=34.1 m/s

So, the ball has greater speed when rotating at 6.04 rev/s.

(b) 1561 m/s^2

The centripetal acceleration of the ball is given by

a=\frac{v^2}{r}

where

v is the speed

r is the distance of the ball from the centre of the trajectory

For situation 1),

v = 30.6 m/s

r = 0.600 m

So the centripetal acceleration is

a=\frac{(30.6 m/s)^2}{0.600 m}=1561 m/s^2

(c) 1292 m/s^2

For situation 2 we have

v = 34.1 m/s

r = 0.900 m

So the centripetal acceleration is

a=\frac{v^2}{r}=\frac{(34.1 m/s)^2}{0.900 m}=1292 m/s^2

5 0
3 years ago
Why does the uv from the sun hurt our eyes. Plz help
Oksanka [162]
Ultraviolet radiation from the sun is controlled by the ozone but if it infiltrates into the atmosphere it becomes a hazard. The uv reaches our eyes and darkens the retina and blurs vision. The fovea becomes insensitive and the cells dormant. This causes gradual blindness.
4 0
3 years ago
When a bicycle coasts uphill, it moves slower and slower as it climbs. Why?
astra-53 [7]

Letter B because it is gaining more potential energy as it SLOWLY climbs up the hill.

the less motion the more potential energy there is

6 0
3 years ago
Read 2 more answers
As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy
Lapatulllka [165]

Answer:

Wavelength, \lambda=0.011\ m

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

f=\dfrac{2.91}{3.67}=0.79\ Hz

The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}

\lambda=0.011\ m

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

8 0
3 years ago
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