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lorasvet [3.4K]
3 years ago
8

What affect does a doubling of the net force have upon the acceleration of the object?

Physics
2 answers:
balandron [24]3 years ago
5 0
F = ma
a = f/m
if f doubled , acc. will be doubled
algol [13]3 years ago
3 0

Answer: It doubles the acceleration of the object.

Explanation: The second Newton's law says that the acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.

This can be written as A = F/m

where A is acceleration, F is force and m is mass.

If we doubled the net force, now we have:

A = (2F)/m = 2(F/m)

So now the acceleration is two times the previous acceleration.

This means that if we double the net force, we also double the acceleration of the object. (notice that this works for ani factor, if we multiply the net force by a real number K, the acceleration also is multiplied by the number K)

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You have a spring with k = 640 N/m connected to a mass with m = 10 kg. You start the system oscillating and measure the velocity
sdas [7]

Answer:

X= 0.5 m

Explanation:

Given that

K= 640 N/m

m=10 kg

v= 4 m/s

We know that

kinetic energy of the mass

KE=1/2 m v²

Potential energy

PE=1/2 k X²

Given that kinetic and potential energy are equal

1/2 k X² = 1/2 m v²

k X² =  m v²

Now by putting the values

640  X² = 10 x 4²

X= 0.5 m

So at 0.5 m  kinetic and potential energy will be equal.

4 0
3 years ago
What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?
satela [25.4K]

Answer:

yes by 30

Explanation:

uhnhuh

5 0
3 years ago
"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th
Semenov [28]

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

7 0
3 years ago
Which equations represent the relationship between wavelength and frequency for a sound wave? Check all that apply. V = f = vf f
Vikentia [17]

It's really hard to make out the gibberish at the end, where the list of choices should be.

Here are the three equations for the relationships among the wavelength, frequency, and wave-speed, for ANY wave:

-- Speed = (wavelength) x (frequency)

-- Wavelength = (Speed) / (frequency)

-- Frequency = (Speed) / (wavelength)

Notice that you only have to remember any ONE of these.  Then you can always get the other ones by multiplying or dividing both sides by the same quantity.

If you want to remember all of them, here are the short forms:

V  =  L · f

L = V / f

f = V / L

6 0
3 years ago
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melisa1 [442]
The correct answer is transmission<<<<<<
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