Answer:
0,020 moles of NaCl
Explanation:
For the reaction:
NaOH + HCl → NaCl + H₂O
The moles of NaOH are:
10,0 mL ≡ 0,0100L × 2,4mol/L = 0,024 moles of NaOH.
In the same way, moles of HCl are:
5,0 mL ≡ 0,0050L × 4,0mol/L = 0,020 moles of HCl.
The limiting reactant is the reactant that is completely used in the reaction.
In this case, as moles of HCl are less than moles of NaOH, limiting reactant is HCl.
That means that moles of NaCl that are produced are the same moles of HCl, <em>0,020 moles</em>
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I hope it helps!
