What is the period (time) that corresponds to oscillatory motion with a frequency of 23.4 Hz when the speed of light is 3.0×10^8
1 answer:
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Answer:
(a) FN = m (g - )
(b) vmin = 17.146 m/s
Explanation:
The radius of the arc is
r = 30m
The normal force acting on the car form the highest point is
FN = m (g - )
If the normal force become 0 we have
m (g - ) = 0
or
g - = 0
This way, when FN = 0, then v = vmin, so
g - = 0
vmin = =
To solve this problem it is necessary to apply the concepts of Work. Work is understood as the force applied to travel a determined distance, in this case the height. The force in turn can be expressed by Newton's second law as the ratio between mass and gravity, as well
Where,
m = mass
h = height
g = Gravitational constant
When it ascends to the second floor it has traveled the energy necessary to climb a height, under this logic, until the 4 floor has traveled 3 times the height h of each of the floors therefore
Replacing in our equation we have to
The correct answer is 4.
Answer:
The correct answer is option A.
Explanation:
Force is defined as push or pull on an object with mass due to which change velocity occurs (acceleration).
if ,v = constant
Net force on the vehilce
F = Normal - Weight
0 = N = W
N = W
So, the force experienced by the object will be due to its mass, and higher the mass more will be the experienced by an object.So, large truck will experience larger net force.