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Tems11 [23]
3 years ago
15

A ray at which angle would produce the most glare? A. 25 degrees B. 59 degrees C. 37 degrees D. 70 degrees

Physics
2 answers:
enyata [817]3 years ago
4 0

The ray more the incidence ray, the more will be the reflected ray. As angle of incidence is to angle of reflection.

Glare can be defined as the difficulty in seeing the object due to more brightness. The bright light such as the direct sunlight or the reflected sunlight or the headlight at the nighttime.The more the intensity the more will be glare.

Hence, the ray that will produce most glare is 70 degree.





GREYUIT [131]3 years ago
3 0

A ray at which angle would produce the most glare is at 70 degrees. The answer is letter D. the greater the incident of light is, the greater is its index of refraction and thus having greater angle to produce a light ray.

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Very easy physics maths about current and other stuffs only one question please help me
Reil [10]

Answer:

The total voltage of the circuit is 18 volts.

Explanation:

We have, three identical resistors of resistance 3 ohms are connected in series in a circuit.

For a series combination, the equivalent resistance is given by the sum of individual resistances i.e.

R_{eq}=R_1+R_2+R_3\\\\R_{eq}=3+3+3\\\\R_{eq}=9\ \Omega

Let V is the voltage of the battery if the current in the circuit is 2 A. So,

V=IR

V=2\times 9\\\\V=18\ V

So, the total voltage of the circuit is 18 volts.

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3 years ago
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OlgaM077 [116]
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Which of the following criteria can help Linda classify gases as greenhouse gases? gas molecules having three or more atoms gas
ratelena [41]
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A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km.A)If you and your spacesuit ha
WITCHER [35]

A) 0.189 N

The weight of the person on the asteroid is equal to the gravitational force exerted by the asteroid on the person, at a location on the surface of the asteroid:

F=\frac{GMm}{R^2}

where

G is the gravitational constant

8.7×10^13 kg is the mass of the asteroid

m = 130 kg is the mass of the man

R = 2.0 km = 2000 m is the radius of the asteroid

Substituting into the equation, we find

F=\frac{(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)(130 kg)}{(2000 m)^2}0.189 N=

B) 2.41 m/s

In order to orbit just above the surface of the asteroid (r=R), the centripetal force that keeps the astronaut in orbit must be equal to the gravitational force acting on the astronaut:

\frac{GMm}{R^2}=\frac{mv^2}{R}

where

v is the speed of the astronaut

Solving the formula for v, we find the minimum speed at which the astronaut should launch himself and then orbit the asteroid just above the surface:

v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)}{2000 m}}=2.41 m/s

3 0
3 years ago
Shelly rolls ball A in the positive x direction with a velocity of 7.5 meters/second. It hits stationary ball B and they undergo
blagie [28]
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