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4 years ago

A ray at which angle would produce the most glare? A. 25 degrees B. 59 degrees C. 37 degrees D. 70 degrees

2 answers:

4 0

The ray more the incidence ray, the more will be the reflected ray. As angle of incidence is to angle of reflection.

Glare can be defined as the difficulty in seeing the object due to more brightness. The bright light such as the direct sunlight or the reflected sunlight or the headlight at the nighttime.The more the intensity the more will be glare.

Hence, the ray that will produce most glare is 70 degree.

GREYUIT [131]4 years ago

3 0

A ray at which angle would produce the most glare is at 70 degrees. The answer is letter D. the greater the incident of light is, the greater is its index of refraction and thus having greater angle to produce a light ray.

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A multiparous client presents to the labor and delivery area in active labor. The initial vaginal examination reveals that the c

balandron [24]

Answer:

correct answer is Precipitous vaginal delivery

Explanation:

given data

cervix dilated = 4 cm

effaced = 100%

delivery = 5 minutes later

solution

correct answer is Precipitous vaginal delivery because precipitous take delivery time less than = 3 hours

A multipara progress at rate 1.5 cm of dilation per hour

and it is progress for 10 cm for the deliver and birth averages approx 20 minute

so here correct answer is Precipitous vaginal delivery

4 0

3 years ago

Where is the sun's energy most concentrated

Maru [420]

B. At the equator

Explanation:

The energy coming from the Sun hits the Earth's surface at different angles, depending on the latitude of the place. The more perpendicular the ray of lights hit the surface, the more the energy transmitted to the Earth's surface, the warmer the location.

The angle at which the ray of lights hit the Earth is related to the latitude: in particular, the ray of lights arrive perpendicular at the equator ( $0^{\circ}$ ), they arrive at larger angle in the United States (which is located at intermediate latitudes) and they arrive at the largest angles at the poles. For this reason, the sun's most energy is concentrated at the equator.

5 0

3 years ago

A magnetic dipole with a dipole moment of magnitude 0.0243 J/T is released from rest in a uniform magnetic field of magnitude 57

ololo11 [35]

Answer:

47.76°

Explanation:

Magnitude of dipole moment = 0.0243J/T

Magnetic Field = 57.5mT

kinetic energy = 0.458mJ

∇U = -∇K

Uf - Ui = -0.458mJ

Ui - Uf = 0.458mJ

(-μBcosθi) - (-μBcosθf) = 0.458mJ

rearranging the equation,

(μBcosθf) - (μBcosθi) = 0.458mJ

μB * (cosθf - cosθi) = 0.458mJ

θf is at 0° because the dipole moment is aligned with the magnetic field.

μB * (cos 0 - cos θi) = 0.458mJ

but cos 0 = 1

(0.0243 * 0.0575) (1 - cos θi) = 0.458*10⁻³

1 - cos θi = 0.458*10⁻³ / 1.397*10⁻³

1 - cos θi = 0.3278

collect like terms

cosθi = 0.6722

θ = cos⁻ 0.6722

θ = 47.76°

7 0

3 years ago

Read 2 more answers

A construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity if he travels a distance o

Anastasy [175]

Answer:

W = 0

Explanation:

We are given with, a construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity. He travels a distance of 50 m.

The work done by an object is given by :

$W=Fd$

F = ma

So,

$W=mad$

m is mass

a is acceleration

d is displacement

The worker is moving with constant velocity, its acceleration will be 0. So, the work done by the worker is 0.

8 0

4 years ago

a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra

Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = $100/\pi$ m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is = $\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l$