A clear cloudless day-time sky is blue because molecules in the air scatter blue light from the sun more than they scatter red light. When we look towards the sun at sunset, we see red and orange colours because the blue light has been scattered out and away from the line of sight.
Average speed is the ratio of total distance moved by Chi in total time interval
So here we will have
Total distance = 100 m + 400 m
![d = 500 m = 0.5 km](https://tex.z-dn.net/?f=d%20%3D%20500%20m%20%3D%200.5%20km)
Total time taken = 5 min + 15 min = 20 min
![T = \frac{20}{60} = \frac{1}{3} hour](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B20%7D%7B60%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20hour)
now by the formula of average speed we know that
![v_{avg} = \frac{d}{T}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7Bd%7D%7BT%7D)
![v_{avg} = \frac{0.5 km}{1/3 h}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7B0.5%20km%7D%7B1%2F3%20h%7D)
![v_{avg} = 1.5 km/h](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%201.5%20km%2Fh)
so average speed will be 1.5 km/h
Answer:
94.1 m
Explanation:
From Coulombs law,
F = Gm1m2/r²................... Equation 1
where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.
Make r the subject of the equation,
r = √(Gm1m2/F)................. Equation 2
Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,
Constant: G = 6.67×10⁻¹¹ Nm²/kg²
Substitute into equation 2
r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)
r √(886.16×10)
r √(88.616×10²)
r = 9.41×10
r = 94.1 m.
Hence the distance of separation = 94.1 m